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just olya [345]
3 years ago
9

What is the average of 30, 40, and 80?

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0
Because 80+40+30 equals 150 then you divide by how many number there are and there are 3 so 150 divided by 3 = 50
Nata [24]3 years ago
6 0
40x80=3200
3200/2=1600
So the answer is 1600
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Find g-1(x) when g(x)=3/5x-9
eimsori [14]

Answer:

g^{-1}(x) = \frac{5x+45}{3}

Step-by-step explanation:

let y = g(x) and rearrange making x the subject

y = \frac{3}{5} x - 9 ( add 9 to both sides )

y + 9 = \frac{3}{5} x

Multiply both sides by 5 to clear the fraction

5y + 45 = 3x ( divide both sides by 3 )

\frac{5y+45}{3} = x

Change y back into terms of x, thus

g^{-1}(x) = \frac{5x+45}{3}

6 0
3 years ago
PLEASE HELP ME 1. A different pool had an area that is of the form
arlik [135]

The solutions to the questions are

  • The number we are using is 5
  • The perfect square number closest to the area is 1024
  • The estimated side length is 32

<h3>What are areas?</h3>

The area of a shape is the amount of space on the shape

For most regular quadrilaterals, you multiply the side lengths to determine the area

<h3>The number to use</h3>

The area expression is given as

Area = ▢ × 102 + ▢ × 101 + 6

From the question, we can use any number

However, this number must be positive

Assume the number is 5

So, we have

Area = 5 × 102 + 5 × 101 + 6

<h3>The perfect square number closest to the result</h3>

In (a), we have:

Area = 5 × 102 + 5 × 101 + 6

Evaluate

Area = 1021

The perfect square number closest to this is

Closest = 1024

<h3>The estimated side length</h3>

In (b), we have

Closest = 1024

Rewrite as

Area = 1024

Take the square roots

Length = 32

Read more about areas at

brainly.com/question/16184187

#SPJ1

6 0
1 year ago
Write 1% as a fraction
RideAnS [48]

It's 1/100

Hope this helps!

8 0
2 years ago
Read 2 more answers
In APQR, the measure of ZR=90°, RQ = 55, PR = 48, and QP = 73. What ratio represents the sine of ZQ?
Irina18 [472]

To find the angle Q we can us the sin law so:

\frac{\sin (Q)}{48}=\frac{\sin (90)}{73}

So we can solve for Q so:

\begin{gathered} \sin (Q)=\frac{48}{73} \\ \measuredangle Q=\sin ^{-1}(0.6) \\ \measuredangle Q=36.87 \end{gathered}

5 0
1 year ago
A piece if wire 40cm is bent to form a right angled triangle whose hypotenuse is 17cm long find the other two sides of triangle
hjlf

Answer: 150mm

Step-by-step explanation:

Take the two adjecent sides of the triangle to be x and y and X is the angle opposite the side, x.

From the trigonometric identities for a right-angled triangle, it is known that

x=170sin X and;

y=170cos X

Thus the perimeter of the triangle is given by

170sin X + 170cos X + 170 = 400

170(sin X + cos X) = 400 - 170

170(sin X + cos X) = 230

sin X + cos X = 230/170 = 1.3529

Squaring both sides hence,

sin^2(X) + 2sin X.cos X + cos^2(X) = 1.8304

Recall that sin^2(X) + cos^2(X) = 1 and 2sin X.cos X = sin 2X.

Thus, the former expression gives;

1 + sin 2X = 1.8304

sin 2X = 0.8304

2X = arcsin (0.8304)

2X = 56.14° or (180 - 56.14)° = 56.14° or 123.86° for X existing within a triangle.

X = 56.14/2 or 123.86/2

X = 28.07° or 61.93°

Thus the two adjacent sides are ;

x = 170 sin (28.07) = 80mm

y = 170 cos (28.07) = 150mm

Using the value of 61.93° as X would give the same values but interchanged for x and y.

I hope you find this useful.

5 0
3 years ago
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