Hello! And thank you for your question!
Use Pemdas to get
3^(n+2)*4=3^28
Rewrite the equation:
3^4(n+2) = 3^28
Cancel the base of 3:
4(n + 2) = 28
Then divide 4 on both sides:
2 + n = 28/4
Simplify 28/4:
2 + n = 7
Subtract 2 on both sides:
n = 7 - 2
Finally simplify 7 - 2:
n = 5
Final Answer:
n = 5
Answer:
<h2>
B. 9</h2>
Step-by-step explanation:
|<-------------- 27 ------------>|
L--------------M----------------N
18 MN
LN = LM + MN
27 = 18 + MN
MN = 27 - 18
<h2>
MN = 9</h2>
Answer:

Step-by-step explanation:
Given
The above table
Required
Determine the probability of a sum that is a multiple of 6
Represent the event that an outcome is a multiple of 6 with M.
List out all possible values of M

Number of M is

Total possible outcome is:

The theoretical probability is then calculated as follows:

In this case, it is:


Simplify fraction

Answer:0.5, 0.5
Step-by-step explanation:
Given

Also, A and B are independent events. So, we can write that


So, the two most possible value of
are 
Answer:
B
Step-by-step explanation:
I'm not really sure tho