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Tatiana [17]
2 years ago
14

Use the quadratic formula x^2-5x+3=0

Mathematics
1 answer:
kifflom [539]2 years ago
5 0

Answer:

x^2 -5x +3 = 0\\\\ x= \frac{-b \pm \sqrt{b^2-4*a*c} }{2a} \\\\b = -5, a = 1 , c = 3\\\\x= \frac{-b + \sqrt{b^2-4*a*c} }{2a} , x= \frac{-b -\sqrt{b^2-4*a*c} }{2a}\\\\x= \frac{5 + \sqrt{25-12} }{2}, x= \frac{5-\sqrt{25-12} }{2}\\\\x= \frac{5+\sqrt{13} }{2}, x= \frac{5- \sqrt{13} }{2}

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Answer:

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Step-by-step explanation:

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8 0
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denpristay [2]
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3 years ago
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Answer quickly for brainliest.
Ratling [72]

Answer:

the <u>one all the way on the left</u> and the <u>one all the way on the right!</u>

<u />

<u>the points that match are </u><em><u> t,b</u></em><u>     </u><em><u>a,v</u></em><u>    </u><em><u> u,c </u></em>

Step-by-step explanation:

Congruent Triangles - Two angles and included side (ASA) Definition: Triangles are congruent if any two angles and their included side are equal in both triangles. There are five ways to test that two triangles are congruent. This is one of them (ASA).

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