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Tatiana [17]
3 years ago
14

Use the quadratic formula x^2-5x+3=0

Mathematics
1 answer:
kifflom [539]3 years ago
5 0

Answer:

x^2 -5x +3 = 0\\\\ x= \frac{-b \pm \sqrt{b^2-4*a*c} }{2a} \\\\b = -5, a = 1 , c = 3\\\\x= \frac{-b + \sqrt{b^2-4*a*c} }{2a} , x= \frac{-b -\sqrt{b^2-4*a*c} }{2a}\\\\x= \frac{5 + \sqrt{25-12} }{2}, x= \frac{5-\sqrt{25-12} }{2}\\\\x= \frac{5+\sqrt{13} }{2}, x= \frac{5- \sqrt{13} }{2}

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Solve the equation. Check your solutions.<br> |4b+4|=|2b+8|
anzhelika [568]

Answer:

<h2><u>b = 2 or b = -2</u></h2>

Explanation:

|4b + 4| = |2b + 8|

<em>Solve absolute value</em>

|4b + 4| = |2b + 8|

Either 4b + 4 = 2b + 8 or 4b + 4 = −(2b + 8)

4b + 4 = 2b + 8 <em>(Possibility 1)</em>

4b + 4 − 2b = 2b + 8 − 2b <em>(Subtract 2b from both sides)</em>

2b + 4 = 8

2b + 4 − 4 = 8 − 4 <em>(Subtract 4 from both sides)</em>

2b = 4

2b / 2 = 4 / 2 <em>(Divide both sides by 2)</em>

b = 2

4b + 4 = −(2b + 8) <em>(Possibility 2)</em>

4b + 4 = −2b − 8 <em>(Simplify both sides of the equation)</em>

4b + 4 + 2b = −2b − 8 + 2b <em>(Add 2b to both sides)</em>

6b + 4 = −8

6b + 4 − 4 = −8 − 4 <em>(Subtract 4 from both sides)</em>

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