1+7 ehhehe ndneje behe

Cups of sugar is 3/4, cups of butter is 1/8 what is the number of cups of sugar for each cup of butter

defon

7 cup of sugar for 1 cup of butter

5 0

3 years ago

The population of weights of a particular fruit is normally distributed, with a mean of 464 grams and a standard deviation of 6

igomit [66]

Answer:

If 27 fruits are picked at random, then 2% of the time, their mean weight will be greater than 466.37 grams

Step-by-step explanation:

Mean = $\mu = 464$

Standard deviation = $\sigma = 6$

We are supposed to find If 27 fruits are picked at random, then 2% of the time, their mean weight will be greater than how many grams i.e.P(X>x)=0.02

The mean weight is in the highest 2%, you want to go to a z-table and find the z-score that where the area to the left of the curve is closest to 0.98.

n = 27

Refer the z -table

P(Z>x)=2.06

$\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}=2.06\\\frac{x-464}{\frac{6}{\sqrt{27}}}=2.06\\x-464=2.06 \times \frac{6}{\sqrt{27}}\\x=(2.06 \times \frac{6}{\sqrt{27}})+464\\x=466.37$

So, If 27 fruits are picked at random, then 2% of the time, their mean weight will be greater than 466.37 grams

7 0

3 years ago

(CO 3) On average, the parts from a supplier have a mean of 97.5 inches and a standard deviation of 6.1 inches. Find the probabi

ololo11 [35]

Answer:

C. Probability is 0.90, which is inconsistent with the Empirical Rule.

Step-by-step explanation:

We have been given that on average, the parts from a supplier have a mean of 97.5 inches and a standard deviation of 6.1 inches.

First of all, we will find z-score corresponding to 87.5 and 107.5 respectively as:

$z=\frac{x-\mu}{\sigma}$

$z=\frac{87.5-97.5}{6.1}$

$z=\frac{-10}{6.1}$

$z=-1.6393$

$z\approx-1.64$

$z=\frac{x-\mu}{\sigma}$

$z=\frac{107.5-97.5}{6.1}$

$z=\frac{10}{6.1}$

$z=1.6393$

$z\approx 1.64$

Now, we need to find the probability $P(-1.64$ .

Using property $P(a$ , we will get:

$P(-1.64$

From normal distribution table, we will get:

$P(-1.64$

Since the probability is 0.90, which is inconsistent with the Empirical Rule, therefore, option C is the correct choice.

6 0

3 years ago

Lee Company has a current ratio of 2.65. The acid test ratio is 2.01. The current liabilities of Lee are $45,000. Assuming there

Salsk061 [2.6K]

The dollar amount of merchandise inventory is A. $28,800
Let N = be the missing number
1.) N/$45,000 = 2.65/1 (cross multiply to get the current assets)
N = $119,250
2.) N/$45,000 = 2.01 (cross multiply to get current the quick assets)
N = $90,450
3.) Since there are no prepaid expenses, subtract current quick assets from the current assets to get the merchandise inventory
$119,250 - $90,450 = $28,800

8 0

3 years ago

Waht is 2t2 math fir math clas

Lelechka [254]

2+2 is 4 LOL you just gotta add 1+1+1+1

4 0

3 years ago

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