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MAVERICK [17]
3 years ago
6

Бах — 4y = 152 3-76 y =

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

y= -38 + 3ax/ 2

Step-by-step explanation:

isolate the variable by dividing each side by factors that don't contain the variable

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Solve the inequality below. Use the drop-down menus to describe the solution and its graph.
katrin [286]

Answer: The Solution to inequality is _______ (x < -4). A graph of the solution should have______  (A filled-in circle at -4) and should be shaded to the ____ (left)

Hope this helps! Please people give more explantions like this Y'ALL MAKE IT COMPLICATED! :)

4 0
2 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
What is the midpoint of the line segment with endpoints?
ella [17]

Answer:

B. (1,2)

Step-by-step explanation:

Look at the image down below!! (ノ◕ヮ◕)ノ*:・゚✧

6 0
3 years ago
222+203 is rounded up to what?
miskamm [114]
222: 220 \\ 203 = 200 \\ \\ 222 + 203 = 425 \\ 220 + 200 = 420 \\ \\ \\ \\ Good \\ luck \\ on \\ your \\ assignment \\ \\ enjoy \\ your \\ day \\ \\ \\ MeIsKaitlyn :)


Remember↓

1-5 would rounded downward
6-9 would be rounded upward 
3 0
3 years ago
Please show how you got the answer, thanks.
FrozenT [24]

Answer:

15.7 feet

Step-by-step explanation:

What we are looking for here is the perimeter/circumference of the table. The formula for the circumference of a circle is diameter x pi. The diameter is 2x the radius so I did 5 x 3.14, 3.14 being in place for pi. Hope this helps! : )

5 0
2 years ago
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