Answer:
53.2 feet
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In the right triangle ABC
-----> by TOA (opposite side divided by the adjacent side)
substitute the values

solve for h


therefore
The height of the pole is

Answer:
The translation would be
X = 40% + 5 + A
Step-by-step explanation:
First, translate the words, is, more than and 'the number'.
Is means equals (=).
More Than means plus (+).
'the number' can be x.
Now, put it together.
X(The Number) =(Is) 40% +(more than) 5 +(more than) A(a number)
I hope this helps!!
Answer:
Total amount of fruits
40 apples and 15 oranges
Step-by-step explanation:
Is there answer choices? Without context I will suggest
Total amount of fruits
40 apples and 15 oranges
Anything with 40 being added to an amount of 15 to get a total of 55
Answer:
(d) m∠AEB = m∠ADB
Step-by-step explanation:
The question is asking you to compare the measures of two inscribed angles. Each of the inscribed angles intercepts the circle at points A and B, which are the endpoints of a diameter.
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<h3>applicable relations</h3>
Several relations are involved here.
- The measures of the arcs of a circle total 360°
- A diameter cuts a circle into two congruent semicircles
- The measure of an inscribed angle is half the measure of the arc it intercepts
<h3>application</h3>
In the attached diagram, we have shown inscribed angle ADB in blue. The semicircular arc it intercepts is also shown in blue. A semicircle is half a circle, so its arc measure is half of 360°. Arc AEB is 180°. That means inscribed angle ADB measures half of 180°, or 90°. (It is shown as a right angle on the diagram.)
If Brenda draws angle AEB, it would look like the angle shown in red on the diagram. It intercepts semicircular arc ADB, which has a measure of 180°. So, angle AEB will be half that, or 180°/2 = 90°.
The question is asking you to recognize that ∠ADB = 90° and ∠AEB = 90° have the same measure.
m∠AEB = m∠ADB
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<em>Additional comment</em>
Every angle inscribed in a semicircle is a right angle. The center of the semicircle is the midpoint of the hypotenuse of the right triangle. This fact turns out to be useful in many ways.