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3 years ago

4+ 3/6 + 2/6! It’s zearn!!

Mathematics

2 answers:

Bas_tet [7]3 years ago

8 0

Answer:

<u>=29/6</u>

Step-by-step explanation:

4+3/6+2/6

=4+1/2+2/6

=9/2+2/6

=9/2+1/3

=29/6

lutik1710 [3]3 years ago

5 0

Answer:

4 5/6 = 29/6 = 4.833333333

Step-by-step explanation:

4+3/6+2/6

Reduce the fraction 3/6 to lowest terms by extracting and canceling out 3.

4+1/2+2/6

Convert 4 to fraction 8/2

8/2+1/2+2/6

Since 8/2 and 1/2 have the same denominator, add them by adding their numerators.

8+1 / 2 + 2/6

Add 8 and 1 to get 9.

9/2 + 2/6

Reduce the fraction 2/6 to lowest terms by extracting and canceling out 2.

9/2 + 1/3

Least common multiple of 2 and 3 is 6. Convert 9/2 and 1/3 to fractions with denominator 6.

27/6 + 2/6

Since 27/6 and 2/6 have the same denominator, add them by adding their numerators.

27+2 / 6

Add 27 and 2 to get 29.

29/6

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Glenn bought 3 pounds of tomatoes. He used § of them to make sauce.

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Answer:i dont kno what number u put

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3 years ago

What is 6 1/4 x 3 3/5

aliya0001 [1]

Answer:

Step-by-step explanation:

Change mixed fraction to improper fraction. Then reduce to lowest term if possible.

6 1/4 x 3 3/5 = 25/4 * 18/5 = 25* 18 /4*5

= 5 * 18 / 4 {giving by 5th table}

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= 45/2

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3 years ago

Alyssa is learning to drive her parents' car. • • • • She increases her speed for 20 seconds. She slows down for 10 seconds. She

anygoal [31]

<h3>Answer: Choice D</h3>

Explanation:

Any time Alyssa is increasing her speed, the graph will move uphill when going from left to right.

If she slows down, then the graph will move downhill when going left to right.

Always move from left to right when reading a graph because this is how the time axis is set up.

Any flat part represents portions where her speed is constant, i.e. doesn't change.

With all that in mind, the answer is choice D because

The first portion is going uphill (she's increasing her speed). This portion spans horizontally from 0 seconds to 20 seconds.
The next portion is her slowing down (the graph is going downhill). This portion spans horizontally from 20 seconds to 30 seconds (so we have a 10 second duration).
The third portion is where Alyssa is driving at some fixed speed that doesn't change. This portion is 20 seconds long.
The last portion is Alyssa slowing down and coming to a complete stop. This portion is 5 seconds long.

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3 years ago

The equation 2x2 − 12x + 1 = 0 is being rewritten in vertex form. Fill in the missing step. Given 2x2 − 12x + 1 = 0 Step 1 2(x2

Bezzdna [24]

Answer:

Part 1) $2(x-3)^{2}-17=0$ (the missing steps in the explanation)

Part 3) (8, 4); The vertex represents the maximum profit

Part 4) x = 3.58, 0.42

Part 5) x = 6, x = 44; The zeros represent the number of monthly memberships where no profit is made

Part 6) 2(x − 7)2 + 118; x = $7

Part 7) The maximum height of the puck is 4 feet. −(x − 4)^2 + 6

Part 8) (x + 3)^2 − 4

Part 9) 2(x − 1)^2 = 4

Part 10) 8(x − 4)^2 + 592

Step-by-step explanation:

Part 1) we have

$2x^{2} -12x+1=0$

Convert to vertex form

step 1

Factor the leading coefficient and complete the square

$2(x^{2} -6x)+1=0$

$2(x^{2} -6x+9)+1-18=0$

step 2

$2(x^{2} -6x+9)+1-18=0$

$2(x^{2} -6x+9)-17=0$

step 3

Rewrite as perfect squares

$2(x-3)^{2}-17=0$

Part 3) we have

$f(x)=-x^{2}+16x-60$

we know that

This is the equation of a vertical parabola open downward

The vertex is a maximum

Convert to vertex form

$f(x)+60=-x^{2}+16x$

Factor the leading coefficient

$f(x)+60=-(x^{2}-16x)$

Complete the squares

$f(x)+60-64=-(x^{2}-16x+64)$

$f(x)-4=-(x^{2}-16x+64)$

Rewrite as perfect squares

$f(x)-4=-(x-8)^{2}$

$f(x)=-(x-8)^{2}+4$

The vertex is the point (8,4)

The vertex represent the maximum profit

Part 4) Solve for x

we have

$-2(x-2)^{2}+5=0$

$-2(x-2)^{2}=-5$

$(x-2)^{2}=2.5$

square root both sides

$(x-2)=(+/-)1.58$

$x=2(+/-)1.58$

$x=2(+)1.58=3.58$

$x=2(-)1.58=0.42$

Part 5) we have

$f(x)=-x^{2}+50x-264$

we know that

The zeros or x-intercepts are the value of x when the value of the function is equal to zero

In this context the zeros represent the number of monthly memberships where no profit is made

To find the zeros equate the function to zero

$-x^{2}+50x-264=0$

$-x^{2}+50x=264$

Factor -1 of the leading coefficient

$-(x^{2}-50x)=264$

Complete the squares

$-(x^{2}-50x+625)=264-625$

$-(x^{2}-50x+625)=-361$

$(x^{2}-50x+625)=361$

Rewrite as perfect squares

$(x-25)^{2}=361$

square root both sides

$(x-25)=(+/-)19$

$x=25(+/-)19$

$x=25(+)19=44$

$x=25(-)19=6$

Part 6) we have

$-2x^{2}+28x+20$

This is a vertical parabola open downward

The vertex is a maximum

Convert the equation into vertex form

Factor the leading coefficient

$-2(x^{2}-14x)+20$

Complete the square

$-2(x^{2}-14x+49)+20+98$

$-2(x^{2}-14x+49)+118$

Rewrite as perfect square

$-2(x-7)^{2}+118$

The vertex is the point (7,118)

therefore

The video game price that produces the highest weekly profit is x=$7

Part 7) we have

$f(x)=-x^{2}+8x-10$

Convert to vertex form

$f(x)+10=-x^{2}+8x$

Factor -1 the leading coefficient

$f(x)+10=-(x^{2}-8x)$

Complete the square

$f(x)+10-16=-(x^{2}-8x+16)$

$f(x)-6=-(x^{2}-8x+16)$

Rewrite as perfect square

$f(x)-6=-(x-4)^{2}$

$f(x)=-(x-4)^{2}+6$

The vertex is the point (4,6)

therefore

The maximum height of the puck is 4 feet.

Part 8) we have

$x^{2}+6x+5$

Convert to vertex form

Group terms

$(x^{2}+6x)+5$

Complete the square

$(x^{2}+6x+9)+5-9$

$(x^{2}+6x+9)-4$

Rewrite as perfect squares

$(x+3)^{2}-4$

Part 9) we have

$2x^{2}-4x-2=0$

This is the equation of a vertical parabola open upward

The vertex is a minimum

Convert to vertex form

Factor 2 the leading coefficient

$2(x^{2}-2x)-2=0$

Complete the square

$2(x^{2}-2x+1)-2-2=0$

$2(x^{2}-2x+1)-4=0$

Rewrite as perfect squares

$2(x-1)^{2}-4=0$

$2(x-1)^{2}=4$

The vertex is the point (1,-4)

Part 10) we have

$8x^{2}-64x+720$

This is the equation of a vertical parabola open upward

The vertex is a minimum

Convert to vertex form

Factor 8 the leading coefficient

$8(x^{2}-8x)+720$

Complete the square

$8(x^{2}-8x+16)+720-128$

$8(x^{2}-8x+16)+592$

Rewrite as perfect squares

$8(x-4)^{2}+592$

the vertex is the point (4,592)

The population has a minimum at x=4 years ( that is after 4 years since 1998 )

6 0

3 years ago

Find the area of trapezium where area=5cm base=6cm height=8cm

Jlenok [28]

Answer:

44cm2

Step-by-step explanation:

[8×(5+6)]/2

=(8×11)/2

=88/2

=44cm2

6 0

2 years ago