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3 years ago

The chart shows data for four moving objects. Which object has the greatest acceleration?

Physics

1 answer:

anygoal [31]3 years ago

3 0

Answer:

عحخهلوتاغلؤابلصاضثتنقيلمةبكاولتوكانلظمبتنياساشرلىؤىة

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Nancy is pushing her empty grocery cart at a rate of 1.8 m/s. 30 seconds later,

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A small block with mass 0.0350 kgkg slides in a vertical circle of radius 0.550 mm on the inside of a circular track. During one

Lisa [10]

Answer:

W_net = μ 5.58, μ = 0.1 W_net = 0.558 J

Explanation:

The work is defined by the related

W = F. d = F d cos θ

where bold indicates vectors.

In the case, the work of the friction force on a circular surface is requested.

The expression for the friction force is

fr = μ N

the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1

W = - fr d

the path traveled half the length of the circle

L = 2 π R

d = L / 2

d = π R

we substitute

W = - μ N d

Total work is initial to

W_neto = - μ π R (N_b - N_a)

let's calculate

W_net = - μ π 0.550 (0.670 - 3.90)

W_net = μ 5.58

for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1

W_net = 0.1 5.58

W_net = 0.558 J

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3 years ago

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3 years ago

A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0

viktelen [127]

Hi there!

Initially, we have gravitational potential energy and kinetic energy. If we set the zero-line at H2 (12.0m), then the ball at the second building only has kinetic energy.

We also know there was work done on the ball by air resistance that decreased the ball's total energy.

Let's do a summation using the equations:
$KE = \frac{1}{2}mv^2 \\\\PE = mgh$

Our initial energy consists of both kinetic and potential energy (relative to the final height of the ball)

$E_i = \frac{1}{2}mv_i^2 + mg(H_1 - H_2)$

Our final energy, since we set the zero-line to be at H2, is just kinetic energy.

$E_f = \frac{1}{2}mv_f^2$

And:
$W_A = E_i - E_f$

The work done by air resistance is equal to the difference between the initial energy and the final energy of the soccer ball.

Therefore:
$W_A = \frac{1}{2}mv_i^2 + mg(H_1 - H_2) - \frac{1}{2}mv_f^2$

Solving for the work done by air resistance:
$W_A = \frac{1}{2}(.450)(15.1^2)+ (.450)(9.8)(30.2 - 12) - \frac{1}{2}(.450)(19.89^2)$

$W_A = \boxed{42.552 J}$

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2 years ago

The chart shows data for four moving objects. Which object has the greatest acceleration? ​

The chart shows data for four moving objects. Which object has the greatest acceleration?