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tia_tia [17]
3 years ago
11

The chart shows data for four moving objects. Which object has the greatest acceleration? ​

Physics
1 answer:
anygoal [31]3 years ago
3 0

Answer:

عحخهلوتاغلؤابلصاضثتنقيلمةبكاولتوكانلظمبتنياساشرلىؤىة

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Convert 15 litre into cubic metre​
atroni [7]

Answer:

0.015m^3

Explanation:

1 m^3 = 1000 liters

x m^3 = 15 liters

Cross multiply

xm^3 x 1000 l = 15 l

Divide both sides by 1000

xm^3 x1000/1000 = 15/1000

xm^3 = 0.015m^3

Therefore 15 liter = 0.015m^3

5 0
3 years ago
What voltage would produce a current of 100amps through an aluminum wire assuming that the re sistance of the wire is3.44×10-4 o
agasfer [191]
V = IR

I = current
R = resistance

Voltage = 100 * (3.44x 10^-4) = do the calculation

Hope this helps
8 0
3 years ago
Before digital filmmaking, what tool was used to control the speed of movement on the screen after filming?
nikitadnepr [17]

Answer:

The appropriate response is "Optical printer ".

Explanation:

  • A photographic printer used mostly for optical aberrations, comprised simply of either a camera that captures the frame to expand, minimize, deform, respectively. through magnifying lenses.
  • A projector that always, as distinct from some kind of touch printer, transferred the image to something like the printing supply.
4 0
4 years ago
Why does a dropped feather hit the ground later than a rock dropped at the same time? *
MissTica
The air resistance on the feather would be the correct answer. 
7 0
3 years ago
Read 2 more answers
Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
stira [4]

Answer:

i) 24.5 m/s

ii) 30,656 m

iii) 89,344 m

Explanation:

Desde una altura de 120 m se deja caer un cuerpo. Calcule a 2.5 s i) la velocidad que toma; ii) cuánto ha disminuido; iii) cuánto queda por hacer

i) Los parámetros dados son;

Altura inicial, s = 120 m

El tiempo en caída libre = 2.5 s

De la ecuación de caída libre, tenemos;

v = u + gt

Dónde:

u = Velocidad inicial = 0 m / s

g = Aceleración debida a la gravedad = 9.81 m / s²

t = Tiempo de caída libre = 2.5 s

Por lo tanto;

v = 0 + 9.8 × 2.5 = 24.5 m / s

ii) El nivel que el cuerpo ha alcanzado en 2.5 segundos está dado por la relación

s = u · t + 1/2 · g · t²

= 0 × 2.5 + 1/2 × 9.81 × 2.5² = 30.656 m

iii) La altura restante = 120 - 30.656 = 89.344 m.

6 0
3 years ago
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