Capillary tube is a type of A. flow component B. thermostat C. Controller D. sensor

A 9.8-g bullet is fired into a stationary block of wood having mass m = 5.04 kg. The bullet imbeds into the block. The speed of

pogonyaev

Answer:

313.8 m/s

Explanation:

Momentum p must be conserved.

The momentum before the collision:

$p=m_{bullet}v_{bullet} + m_{block}v_{block}$

The momentum after the collision:

$p=(m_{bullet}+m_{block})v_{bullet+block}$

Solving both equations:

$v_{bullet}=\frac{(m_{bullet}+m_{block})v_{bullet+block}}{m_{bullet}}$

6 0

4 years ago

The charges of two particles are as follows: Q1=2 x 10 -8 C and Q2 = 3 x 10 -7 C. Find the magnitude of the force between these

Fantom [35]

Answer:

F = 3.86 x 10⁻⁶ N

Explanation:

First, we will find the distance between the two particles:

$r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2}\\$

where,

r = distance between the particles = ?

(x₁, y₁, z₁) = (2, 5, 1)

(x₂, y₂, z₂) = (3, 2, 3)

Therefore,

$r = \sqrt{(3-2)^2+(2-5)^2+(3-1)^2}\\r = 3.741\ m\\$

Now, we will calculate the magnitude of the force between the charges by using Coulomb's Law:

$F = \frac{kq_{1}q_{2}}{r^2}\\$

where,

F = magnitude of force = ?

k = Coulomb's Constant = 9 x 10⁹ Nm²/C²

q₁ = magnitude of first charge = 2 x 10⁻⁸ C

q₂ = magnitude of second charge = 3 x 10⁻⁷ C

r = distance between the charges = 3.741 m

Therefore,

$F = \frac{(9\ x\ 10^9\ Nm^2/C^2)(2\ x\ 10^{-8}\ C)(3\ x\ 10^{-7}\ C)}{(3.741\ m)^2}\\$

5 0

3 years ago

When a trebuchet counterweight is hoisted by soldiers, what form of energy is

vladimir1956 [14]

10. A safe place to use the trebuchet would be away from other buildings and people. A good example of a place would be a large field with no nearby structures.
14. Many factors need to be kept consistent throughout the experiment. One example of a variable that would need to be consistent is the weight and size of the projectile.
15. It is important to do many trials so that you can make sure that the results of each trial are nearly the same. If they are all vastly different, then it means that something has gone wrong.

Sorry I was only able to answer a few questions, but I hope these few answers help! :)

4 0

3 years ago

Read 2 more answers

A 2200 kg car doubles its speed from 50 km/hr to 100 km/hr. By how many times does the kinetic energy from the car’s forward mot

Firlakuza [10]

Answer: 4

Explanation:

Given that:

Mass of car M = 2200 kg

Initial speed Vi = 50 km/hr

Final speed Vf = 100 km/hr

Kinetic energy is the energy possessed by a moving object. It is measured in joules, and depends on the mass (m) of the object and the speed (v) by which it moves

i.e K.E = 1/2MV^2

So, when traveling at 50 km/h

KE = 1/2x 2200kg x (50km/h)^2

KE = 0.5 x 2200 x 2500

KE1 = 2750000J

So, when traveling at 100 km/h

KE = 1/2x 2200 x (100 km/h)^2

KE = 0.5 x 2200 x 10000

KE2 = 11000000J

Thus, the number of times kinetic energy increases is obtained by dividing KE2 by KE1

i.e 11000000J / 2750000J

= 4

Thus, the kinetic energy from the car’s forward motion increase 4 times

5 0

3 years ago

Read 2 more answers

For a person with a Near Point (NP) = 45 cm, what would be his prescription's lens power = _________ diopters A) 1.08 diopters

natita [175]

Answer:

The power of lens is 2.22 D.

Explanation:

Given that,

Distance of image v= 45 cm

We know that,

Distance of object u= ∞

Power of lens is the reciprocal of focal length.

$P=\dfrac{1}{f}$

We need to calculate the power of lens

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

Where, f = focal length

v = image distance

u = object distance

Put the value into the formula

$\dfrac{1}{f}=\dfrac{1}{45}+\dfrac{1}{\infty}$

$\dfrac{1}{f}=\dfrac{1}{0.45}+0$

$P=\dfrac{1}{f}=2.22$

Hence, The power of lens is 2.22 D.

7 0

3 years ago