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joja [24]
3 years ago
13

A small block with mass 0.0350 kgkg slides in a vertical circle of radius 0.550 mm on the inside of a circular track. During one

of the revolutions of the block, when the block is at the bottom of its path, point AA, the magnitude of the normal force exerted on the block by the track has magnitude 3.90 NN . In this same revolution, when the block reaches the top of its path, point BB, the magnitude of the normal force exerted on the block has magnitude 0.670 NN . Part A How much work was done on the block by friction during the motion of the block from point AA to point BB
Physics
1 answer:
Lisa [10]3 years ago
7 0

Answer:

 W_net = μ 5.58,   μ = 0.1     W_net = 0.558 J

Explanation:

The work is defined by the related

          W = F. d ​​= F d cos θ

where bold indicates vectors.

In the case, the work of the friction force on a circular surface is requested.

The expression for the friction force is

              fr = μ N

the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1

               W = - fr d

the path traveled half the length of the circle

               L = 2 π R

               d = L / 2

               d = π R

we substitute

                 W = - μ N d

Total work is initial to

                W_neto = - μ π R (N_b - N_a)

let's calculate

                W_net = - μ π 0.550 (0.670 - 3.90)

                W_net = μ 5.58

for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1

                W_net = 0.1 5.58

                W_net = 0.558 J

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y = 0m

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v0y = 0 m/s

g = 9.8 m/s^2

t = ?


Solve for t:

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Now, using time, we can solve for the range using the equation:


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3 0
4 years ago
Read 2 more answers
On a 100m straight track, Zak runs to the 80m mark in 15s. He then runs back to the 20m in 10s. He then runs to the 100m mark in
drek231 [11]

Answer:

The total distance traveled by Zak is 250 m and total displacement is

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Explanation:

<u><em>Distance</em></u> is a scalar quantity that represents how much ground an

object has covered during its motion

<u><em>Displacement</em></u> is a vector quantity that represents how far out of place

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Displacement = final position - initial position

The straight track is 100 m

Zak runs to the 80 m mark

That means he runs forward from zero to 80

Then his distance = 80 m

His displacement = + 80 m

He then runs back to the 20 m

That means that he runs back from 80 m to 20 m

Then his distance = 80 - 20 = 60 m

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That means he runs forward from 20 m to 100 m

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His displacement = 70 - 100 = - 30 m

His total distance is the sum of all distances he runs

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His total displacements is the sum of all displacements he runs

The total displacement = (+80) + (-60) + (+80) + (-30) = + 70 m

<em>The total distance traveled by Zak is 250 m and total displacement is</em>

<em>70 m</em>

3 0
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1. A plane flying a triangular patter flies 150 km[N], then 400 km(E). What is the total displacement of the
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Answer:

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1. A = 150 km North

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