Answer:
Here is the answer...hope it helps:)
Answer:
a) 
b) 
c) 5
Step-by-step explanation:
<span>(a) 2.09302406
(b) Lower limit of 95% confidence interval = 185.85
(a) To get the t-score, first determine the number of degrees of freedom you have. That's simply the number of samples minus 1, so in this case we have 19 degrees of freedom. Then calculate (1-0.95)/2 = 0.05/2 = 0.025 which is the size of the tail for the confidence interval you want. Finally, lookup in a T-Distribution Table for the 19 degrees of freedom and tail size. The value looked up will be 2.09302406.
(b) Once you have the t-score, to calculate your desired interval, calculate the following:
V = T*SD/sqrt(n)
where
V = Variance
T = T-score
SD = Standard deviation
n = number of samples
So let's plug in the values and calculate V
V = T*SD/sqrt(n)
V = 2.09302406*21.02/sqrt(20)
V = 2.09302406*21.02/4.472135955
V = 43.99536574/4.472135955
V = 9.837662849
Your 95% confidence interval is now the mean +/- V. So
lower limit = 195.69 - 9.84 = 185.85
upper limit = 195.69 + 9.84 = 205.53</span>
In 5 hours, bus travel = 153 miles
Now, just divide 5 from 153, in order to calculate the distance in 1 hour.
It would be: 153 / 5 = 30.6
In short, Your Answer would be 30.6 miles
Hope this helps!
