We have that
x² + 8x + y²<span> - 16y = 0
</span>Group
terms that contain the same variable<span>
(x</span>²+8x)+(y²-16y)=0
Complete
the square twice. Remember to balance the equation by adding the same constants
to each side
(x²+8x+16)+(y²-16y+64)=16+64
Rewrite as perfect squares
(x+4)²+(y-8)²=80
circle with a center (-4,8) and radius √80 units
<span>
and
x</span>² + 8x + y² - 8y = 32
Group
terms that contain the same variable
(x² + 8x) + (y² - 8y) = 32
Complete
the square twice. Remember to balance the equation by adding the same constants
to each side
(x² + 8x+16) + (y² - 8y+16) = 32+16+16
<span>Rewrite as perfect squares</span>
(x+4)² + (y-4)² =64
circle with a center (-4,4) and radius 8 units
using a graph tool
see the attached figure
the solution are the points(-12,4) and (4,4)
we are given two points as
A (1,5) and B (6,2)
so,
x1=1 , y1=5
x2=6 , y2=2
now, we can use distance formula

now, we can plug values
and we get


so, we will get
.........Answer
Answer:
<u><em>x = 4</em></u>
<u><em>x = 3</em></u>
<em><u>x = 10</u></em>
<u><em>x = 3</em></u>
<em><u>x = 16</u></em>
<em><u>x = 35</u></em>
Step-by-step explanation:

x · 10 = 5 · 8
10x = 40
10x ÷ 10 = 40 ÷ 10
<u><em>x = 4</em></u>

x · 8 = 12 · 2
8x = 24
8x ÷ 8 = 24 ÷ 8
<u><em>x = 3</em></u>

x · 3 = 15 · 2
3x = 30
3x ÷ 3 = 30 ÷ 3
<em><u>x = 10</u></em>

x · 12 = 6 · 6
12x = 36
12x ÷ 12 = 36 ÷ 12
<u><em>x = 3</em></u>

x · 2 = 8 · 4
2x = 32
2x ÷ 2 = 32 ÷ 2
<em><u>x = 16</u></em>

x · 2 = 10 · 7
2x = 70
2x ÷ 2 = 70 ÷ 2
<em><u>x = 35</u></em>
Answer:
Hi, you didn't include the diagram for this question but please find it in the attachment.
PT = TR = TQ = 12
SQ = PR = 24
m∠QSR = m∠QPR = 23°
m∠STR = m∠PTQ = 134°
m∠SQR = 67°
Step-by-step explanation:
ST = 12 (given)
m∠PRS = 23° (given)
Now for the measures
TQ = ST = 12 (Reason is that point T represents a perpendicular bisector)
PT = TR = 12 (Diagonal SQ and PR are of the same length)
SQ = ST + TQ = 12 + 12 = 24
SQ = 24
PR = SQ = 24
m∠QPR = m∠PRS = 23° (alternate angles)
m∠PSR = 90° (right angle)
m∠QSR = 23° (base angles of an isosceles triangle)
m∠STR + m∠QSR + m∠PRS = 180° (sum of angles in a triangle)
m∠STR + 23° + 23° = 180°
m∠STR = 180° - 46° = 134°
m∠PTQ = m∠STR = 134° (vertically opposite angles)
m∠SQR + m∠QRS + m∠QSR = 180° (sum of angles in a triangle)
m∠SQR + 90° + 23° = 180°
m∠SQR = 180° - 113° = 67°
The answer that your looking for is 141