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3 years ago

Simplify 18 - 2[x + (x - 5)].

1 answer:

7 0

18 - 2[x + (x-5)]
First I would get rid of the inside parenthesis by distributing the + to everything inside and end up with;

18 - 2[x + x - 5]
Then I'd combine like terms inside the brackets
18 - 2[2x - 5]
Then I'd multiply what is inside the brackets by the -2
18 - 4x + 10
I'd combine like terms and end up with:

28 - 4x......or rewritten as -4x + 28

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Find the value of the integral that converges.<br> ∫^-5_-[infinity] x^-2 dx.

Bingel [31]

Answer:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

Step-by-step explanation:

For this case we want to find the following integral:

$\int_{-\infty}^{-5} x^{-2}dx$

And we can solve the integral on this way:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{x^{-2+1}}{-2+1} \Big|_{-\infty}^{-5}$

$\int_{-\infty}^{-5} x^{-2}dx= -\frac{1}{x} \Big|_{-\infty}^{-5}$

And if we evaluate the integral using the fundamental theorem of calculus we got:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

8 0

2 years ago

A stock price is losing value at a rate of 4 cents every minute. After 15 minutes, the price of the stock is $10.24 (1024 cents)

Sveta_85 [38]

Jesus ew math bruh. Anyway let’s sing the campfire

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6 0

2 years ago

The following table gives results from two groups of students who took a nonproctored test. Use a 0.01 significance level to tes

Nana76 [90]

Answer:

Original claim is $\mu_{1} =\mu_{2}$

Opposite claim is $\mu_{1} \neq \mu_{2}$

Null and alternative hypotheses:

$H_{0}:\mu_{1} = \mu_{2}$

$H_{1} : \mu_{1} \neq \mu_{2}$

Significance level: 0.01

Test statistic:

We can use TI-84 calculator to find the test statistic and P-value. The steps are as follows:

Press STAT and the scroll right to TESTS

Scroll down to 2-SampTTest... and scroll to stats.

Enter below information.

$\bar{x_{1}}=70.29$

$Sx1=22.09$

$n_{1} = 30$

$\bar{x_{2}}=74.26$

$Sx2=18.15$

$n_{2} = 32$

$\mu_{1} \neq \mu_{2}$

Pooled: Yes

Calculate.

The output is in the attachment.

Therefore, the test statistic is:

$t=-0.78$

P-value: 0.4412

Reject or fail to reject: Fail to reject

Final Conclusion: Since the p-value is greater than the significance level, we, therefore, fail to reject the null hypothesis and conclude that the there is sufficient evidence to support the claim that the samples are from populations with the same mean.

6 0

2 years ago

Plz plz plz help me with this question

Gnoma [55]

My teacher told be to try and think of it as a circle, because circles are 360 degrees. Then to place those angles in the circle and it should make it easier to find the angles, because when you see it in the circle, you can divide it into 4 parts so that you would then have 4, 90 degree angles that you can then work off of by placing those angles you need to find into the circle. It was supposed to make it easier, and i genuinely hope that you can do this. You got this, and you will get through the pain of math tonight and many more. Good luck. ^-^

8 0

2 years ago

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Ronnie, Mack, Kim, and Ada together stacked a total of 40 pizzas in a pan. Ronnie stacked 0.25 of the pizzas, Mack stacked 9 of

natta225 [31]

Hello!

Here's how much each person stacked:

Ronnie -- 0.25 of the 40 pizzas.

Mack -- 9/40

Kim -- 35% of the 40 pizzas.

Ada -- rest of the pizzas.

Now, the questions asks for who stacked the most pizzas.

First, find our how many pizzas they stacked out of 40.

40 × 0.25 = 10

40 × 35% = 14

10 + 9 + 14 = 33

40 - 33 = 7

This means that Ronnie stacked 10 pizzas, Mack stacked 9 pizzas, Kim stacked 14 pizzas, and Ada stacked 7 pizzas.

ANSWER:

Kim stacked the most pizzas since she stacked 14 of them.

7 0

3 years ago

Read 2 more answers