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3 years ago

I need help please send work

Mathematics

2 answers:

Zigmanuir [339]3 years ago

7 0

I think you have to 26+4 which is 30 I think there is 30 cups

Yuki888 [10]3 years ago

3 0

Remember 1 fluid ounce equals .125 cup

So first do 26 times .125
Which is 3.25

3.25 x 4 equals 13

13 cups

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BRAINLIEST

kenny6666 [7]

Answer:

B. 1 1/3

Step-by-step explanation:

$\frac{5}{6} + \frac{3}{6} = \frac{8}{6}$

$\frac{8}{6} = \frac{4}{3}$

three can go into 4 once, so we have a whole number of 1 and a leftover 1/3.

= $1\frac{1}{3}$

hope this helps :)

4 0

2 years ago

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What are the solutions to 2(x-6)2 = 50 ?

yuradex [85]

Answer:

2(x-6)=50

x-6=50/2

x-6=25

x=31

4 0

3 years ago

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Easyy I need help guys...(easy fractions)

Ivanshal [37]

1a. 5/10 can be simplified to 1/2. (5 divided by 5 is one, 10 divided by 5 is 2.)

1b. 9/12 can be simplified to 3/4. (9 divided by 3 is 3, 12 divided by 3 is 4.)

1c. 12/18 can be simplified to 2/3. (12 divided by 6 is 2, 18 divided by 6 is 3.)

1d. 9/24 can be simplified to 3/8. (9 divided by 3 is 3, 24 divided by 3 is 8.)

1e. 27/90 can be simplified to 3/10. (27 divided by 9 is 3, 90 divided by 9 is 10.)

1f. 40/48 can be simplified to 5/6. (40 divided by 8 is 5, 48 divided by 8 is 6.)

8 0

3 years ago

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What are the domain and range of the inequality y < sqrt x+3+1

love history [14]

Given:

The inequality is:

$y$

To find:

The domain and range of the given inequality.

Solution:

We have,

$y$

The related equation is:

$y=\sqrt{x+3}+1$

This equation is defined if:

$x+3\geq 0$

$x\geq -3$

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

$\sqrt{x+3}\geq 0$

$\sqrt{x+3}+1\geq 0+1$

$y\geq 1$

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

So, the domain of the given inequality is y>1.

Therefore, the correct option is A.

3 0

3 years ago

The sides of the rectangle are in the ratio of 4:7. If its length is 31.5 in., find the width, the perimeter, and the area of th

AveGali [126]

Let $\ell$ the length and $w$ the width. By the ratio of the sides:

$\dfrac{w}{\ell}=\dfrac{4}{7}\Longrightarrow \dfrac{w}{31.5}=\dfrac{4}{7}\Longrightarrow w=\dfrac{4\cdot31.5}{7}\Longrightarrow \boxed{w=18~in.}$

Now, we'll find the perimeter p. We'll use the formula below:

$p=2(\ell+w)\\\\
p=2(31.5+18)\\\\
p=2\cdot49.5\\\\
\boxed{p=99~in.}$

The area of a rectangle is $S=w\cdot\ell$ . Then:

$S=w\cdot\ell\\\\
S=18\cdot31.5\\\\
\boxed{S=567~in.^2}$

8 0

3 years ago

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