56° and 34°
complementary angles sum to 90° thus
3x - 10 + 2x - 10 = 90
5x - 20 = 90
add 20 to both sides of the equation
5x = 90 + 20 = 110
divide both sides by 5
x = = 22
angle 2x - 10 = (2 × 22) - 10 = 44 - 10 = 34° and
angle 3x - 10 = (3 × 22) - 10 = 66 - 10 = 56°
The answer is A triangle can not contain to right angles it may only contain one to be classified as a triangle.Hope this helped unlike the other persons comment lol.
Answer:12
Step-by-step explanation: 0.6 x 20= 12
Simply move -2 to another side.
Distribute -1/3 in (x+6)
---> Answer