Answer:
5.72 grams of O₂ are present in the sample
Explanation:
Let's calculate the moles of O₂ by the Ideal Gases Law.
P . V = n . R . T
1.66 atm . 2.50L = n . 0.082 . 283K
(1.66 atm . 2.50L) / 0.082 . 283K = n
0.179 mol = n
Molar mass O₂ = 32 g/m
Mol . molar mass = mass → 0.179 m . 32g/m = 5.72 g
<span>Which best explains why some radioisotopes decay in a decay series?
</span><span>
The correct answer is:
Some unstable materials decay radioactively into other unstable materials.
</span>Radioactive decay a the spontaneous process through which an unstable atomic nucleus breaks into smaller, more stable fragments. <span>It's basically a matter of thermodynamics. Every atom seeks to be as stable as possible. In the case of radioactive decay, instability occurs when there is an imbalance in the number of </span>protons<span> and </span>neutrons<span> in the atomic nucleus.</span>
Answer:
140 L (141.409 without rounding)
Explanation:
Assuming ideal behavior (so that we can use the ideal gas law), we can plug into the equation PV=nRT. P=2.3 atm, n=7.34 mol, and T=540 K. (If converting from Celsius to Kelvin, add 273.15.) For R, we'll use 0.082057 L*atm/(mol*K) so that the units cancel out. 2.3 atm*V=7.34 mol*.082057 Latm/(molK)*540 K. Divide both sides by 2.3 to get the Volume in liters. That will give you a volume of 140 L (with sig figs. If you don't round it, you'd get 141.409 L).
Answer:
Explanation:
Given that:
P₅₀ = 20 torr in muscle
The partial pressure of O2 in lungs Po₂ = 100 torr
The hill coefficient = 3
According to the Hill coefficient;
here;
= fraction of haemoglobin monomers
= 125 θ lungs
However for θ muscle :
= 125 (θ lungs) - 1 (θ muscle)
= 124
B.
if nh =1
(θ muscle) = 1
(θ lungs) - (θ muscle) = 5 - 1
(θ lungs) - (θ muscle) = 4