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Andre45 [30]
3 years ago
9

Knowing that the protease shows highest activity between pH 4-6, what could be the identity of the base residue acting as a in t

he reaction? Explain and write the expected mechanism for the reaction. b. Assuming that the optimal pH for the reaction strictly depends exclusively on the protonation state of the active site residues at which pH do you expect maximal enzymatic activity? Explain your rationale. c. What is the fraction of deprotonated Cys and protonated B at the calculated optimum pH? d. How these fractions are changing at 1 pH unit below the optimal pH? Which fraction of the enzyme will be active at this pH?
Chemistry
1 answer:
olga_2 [115]3 years ago
8 0

hey there!:

A) Knowing theatre the protease is showing the highest activity at pH 4-6, implies that the amino acid that amino acid that it is acting in is an amino acid with a basic side chain. Therefore, the residues can be any one of the three basic amino acids being histidine, arginine or lysine , having basic side chains at neutral pH.

b) The mechanism of reaction of cysteine proteases is as follows:

 First step in the reaction is the deprotonation of a thiol in the cysteine proteases's active site by an adjacent amino acid with a basic side chain, which might be a histidine residue. This is followed by a nucleophilic attack by the anionic sulfur of the deprotonated cysteine on the substrate carbonyl carbon.

Here, a part of the substrate is released with an amine terminus, restoring the His into a deprotonated form, thus forming a thioester intermediate, forming a link between the carboxy-terminal of the substrate and cysteine, resulting in thiol formation. Thus the name thiol proteases. The thioester bond is then hydrolyzed into a carboxylic acid moiety while again forming the free enzyme.

C) cysteine proteases have a pka of 8-9 but when they are deprotonated by a His residue, their pka would come down to 6-8, which would be their optimal pH for functioning. This is because there is a deprotonation of the thiol group , later restoring the HIS deprotonated form and then formation of a thioester bond. This thioester bond when hydrolysed will a carboxylate moeity , which is responsible for bringing the pH down towards a more acidic side.  

d) at the optimal pH , the fraction of deprotonated cysteine and protonated B will be equal which will change with the change in pH.

Hope this helps!

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Answer : The given compound belongs to ether and alcohol.

Explanation :

The chemical formula of the given compound is, C_5H_{12}O_2

First we have to calculate the degree of unsaturation.

Formula used:

Degree of unsaturation = \frac{2C+2+N-X-H}{2}

where,

C = number of carbon

H = number of hydrogen

N = number of nitrogen

X = number of halogen

Degree of unsaturation = \frac{2\times 5+2+0-0-12}{2}=0

The degree of unsaturation is, 0 that means there is no double or triple bond in the compound only single bond is present between the atoms.

Thus, the given compound belongs to ether and alcohol.

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3 years ago
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Your answer is D. You're Welcome

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Which of the following is a correct balanced equation for the neutralization reaction that occurs
PtichkaEL [24]

Neutralization reaction takes place between an acid and a base to form salt and water.

In the given reaction the acid is hydrochloric acid HCl and the base is aluminum hydroxide (Al(OH)_{3}).

The correct balanced equation for the neutralization reaction that occurs between aluminum hydroxide and hydrochloric acid can be represented as:

Al(OH)_{3}(aq)+ 3HCl(aq) --->AlCl_{3}(aq)+3H_{2}O(l)

Al(OH)_{3}can give 3 hydroxide, OH^{-}ions which can neutralize the 3 H^{+}ion produced by 3 HCl molecules giving 3 mole of water and the salt aluminum chloride, AlCl_{3}.

Therefore the correct option will be.

D. Al(OH)3 + 3 HCl (aq) --> AlCl3(aq) + 3 H2O(l)

3 0
3 years ago
The free energy of formation of nitric oxide, NO, at 1000 K (roughly the temperature in an automobile engine during ignition) is
Assoli18 [71]

<u>Answer:</u> The value of K_p for the chemical equation is 8.341\times 10^{-5}

<u>Explanation:</u>

For the given chemical equation:

N_2(g)+O_2(g)\rightarrow 2NO(g)

To calculate the K_p for given value of Gibbs free energy, we use the relation:

\Delta G=-RT\ln K_p

where,

\Delta G = Gibbs free energy = 78 kJ/mol = 78000 J/mol  (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

T = temperature = 1000 K

K_p = equilibrium constant in terms of partial pressure = ?

Putting values in above equation, we get:

78000J/mol=-(8.314J/Kmol)\times 1000K\times \ln K_p\\\\Kp=8.341\times 10^{-5}

Hence, the value of K_p for the chemical equation is 8.341\times 10^{-5}

4 0
4 years ago
Different solutions of salt X are made up. What volume of: a) a 4 mol/dm³ solution contains 2 moles of X? b) a 6 mol/dm³ solutio
Gelneren [198K]

Answer:

a. 0.5dm³

b. 5x10⁻³dm³

Explanation:

a. A solution that is 4mol/dm³ contains 4 moles in 1dm³. The volume that contains 2 moles is:

2 moles * (1dm³ / 4mol) =

<h3>0.5dm³</h3><h3 />

b. And for the 6 mol/dm³ containing 0.03moles:

0.03 moles * (1dm³ / 6mol) =

<h3>5x10⁻³dm³</h3>
5 0
3 years ago
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