Answer:
3
Step-by-step explanation:
Simplify the following:
((-1^3)/(-3)^(-3))^2
1^3 = 1:
((-1)/(-3)^(-3))^2
(-3)^(-3) = 1/(-1)^3×1/3^3 = (-1)/3^3:
((-1)/((-1)/3^3))^2
3^3 = 3×3^2:
((-1)/(-1/(3×3^2)))^2
3^2 = 9:
((-1)/((-1)/(3×9)))^2
3×9 = 27:
((-1)/((-1)/27))^2
Multiply the numerator of (-1)/((-1)/27) by the reciprocal of the denominator. (-1)/((-1)/27) = (-27)/(-1):
((-27)/(-1))^2
(-27)/(-1) = (-1)/(-1)×27 = 27:
27^2
| 2 | 7
× | 2 | 7
1 | 8 | 9
5 | 4 | 0
7 | 2 | 9:
Answer: 729 = 1/729 thus c: is your Answer
Answer:
17(x-2)
Step-by-step explanation:
Given the expression
17x - 34
We are to factorize it
Get their factors
17x = 17 * x
34 = 17 * 2
Since 17 is common to both factors, hence 17 is the GCF
17x - 34 = 17(x - 2)
Hence the equivalent expression is 17(x-2)
We know that
[area of a circle ]=pi*r²
diameter=4 in
r=4 in/2-----> 2 in
so
area=pi*2²-----> area of the circle=4*pi in²
the answer is
the area, in square inches, of the circle is <span>3.14 • 2²</span>
It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}
