Hi!
So we have to make a system of equations here.
Let sibling 1 be O and sibling 2 be Y (for older and younger)
So:
O + Y = 64
O = 64 - Y
(Either one works)
The older sibling is 6 years older.
O = Y + 6
Make everything in terms of Y.
64 - Y = Y + 6
Same to both:
58 = 2y
2y = 58
Divide by 2 on both sides:
y = 29
Since the older sibling is 6 years older:
29 + 6 = 35
Y = 29
O = 35
Let me know if you have any questions.
Answer:
(10, 14)
Step-by-step explanation:
To solve this system let's use substitution:
Solve the first equation for x, obtaining x = 24 - y, and then substitute 24 - y for x in the second equation:
3(24 - y) + 5y = 100
Performing the indicated multiplication, we get:
72 - 3y + 5y = 100
Combining like terms results in 72 - 100 = -2y, or -28 = -2y
Thus, y must be 14.
If y = 14, then the first equation tells us that x = 10.
Check: Is this true? 3(10) + 5(14) = 100 YES
The solution is (10, 14).
What was it about the questions on the best that you were supposed to compare to this solution?
The second one would be the answer. You want to plug in for this question. You can divide over the five leaving you with (x-2)^2 =25. Since you are squaring this answer, you want to get either 5 or negative five. Both -3 and 7 will do that.
Answer:
B. 51
Step-by-step explanation:
first do inside the parenthesis
83 - 4 * (6-4)^3 = 83 - 4 * (2)^3
now multiply 4 and the third power of 2 (the third power of 2 is 2x2x2=8)
83 - 4 * (2)^3 = 83 - 32 subtract and the answer is 51