Answer:
8.18
Step-by-step explanation:
<u>r = square root of A/ pi </u>
R = square root 210/ 3.14
I hope the <u><em>formula</em></u> helped!
Another effective strategy for helping students improve their mathematics performance is related to solving word problems. More specifically, it involves teaching students how to identify word problem types based on a given problem’s underlying structure, or schema. Before learning about this strategy, however, it is helpful to understand why many students struggle with word problems in the first place.
Difficulty with Word Problems
Most students, especially those with mathematics difficulties and disabilities, have trouble solving word problems. This is in large part because word problems require students to:
Answer:
A = .785 inches ^2
Step-by-step explanation:
C = pi *d
We know the diameter = 2*r
C = pi*2*r
Substituting pi = 3.14 we can solve for r
3.14 = 2*pi*r
3.14 = 2*3.14 *r
Divide by 3.14 on each side
3.14/3.14 = 2*3.14 *r/3.14
1 = 2r
Divide by 2
1/2 =2r/2
1/2 =r
Now we can find the area
A = pi *r^2
A = 3.14 *(1/2)^2
A= 3.14 *1/4
A = .785 inches ^2
Answer:
Increasing if f' >0 and decreasing if f'<0
Step-by-step explanation:
Difference quotient got by getting
will be greater than 0 if function is increasing otherwise negative
Here h is a small positive value.
In other words, we find that whenever first derivative of a function f(x) is positive the function is increasing.
Here given that for x1, x2 where x1<x2, we have
if f(x1) <f(x2) then the function is decreasing.
Or if x1<x2 and if f(x1) >f(x2) for all x1, and x2 in I the open interval we say f(x) is decreasing in I.
