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3 years ago

Please help i’ll give you brainliest and a thanks ❤️

Mathematics

2 answers:

zubka84 [21]3 years ago

7 0

1. 2⁰
2. 2¹
3. 2-¹
4. 2⁰

KengaRu [80]3 years ago

4 0

Answer:

$2^{4} x 2^{-4} ---- 2^{0} \\2^{-4} x 2^{5} ---- 2^{1} \\\frac{2^{4} }{2^{5}} ---- 2^{-1} \\\\\frac{2^{4} }{2^{4}} ---- 2^{0}$

Step-by-step explanation:

(pretend the x's are multiplication signs)

hope this helps you!

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Use the "rule of 72" to estimate the doubling time (in years) for the interest rate, and then calculate it exactly. (Round your

Law Incorporation [45]

Answer:

According to the rule of 72, the doubling time for this interest rate is 8 years.

The exact doubling time of this amount is 8.04 years.

Step-by-step explanation:

Sometimes, the compound interest formula is quite complex to be solved, so the result can be estimated by the rule of 72.

By the rule of 72, we have that the doubling time D is given by:

$D = \frac{72}{Interest Rate}$

The interest rate is in %.

In our exercise, the interest rate is 9%. So, by the rule of 72:

$D = \frac{72}{9} = 8$ .

According to the rule of 72, the doubling time for this interest rate is 8 years.

Exact answer:

The exact answer is going to be found using the compound interest formula.

$A = P(1 + \frac{r}{n})^{nt}$

In which A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

So, for this exercise, we have:

We want to find the doubling time, that is, the time in which the amount is double the initial amount, double the principal.

is double the initial amount, double the principal.

$A = 2P$

$r = 0.09$

The interest is compounded anually, so $n = 1$

$A = P(1 + \frac{r}{n})^{nt}$

$2P = P(1 + \frac{0.09}{1})^{t}$

$2 = (1.09)^{t}$

Now, we apply the following log propriety:

$\log_{a} a^{n} = n$

So:

$\log_{1.09}(1.09)^{t} = \log_{1.09} 2$

$t = 8.04$

The exact doubling time of this amount is 8.04 years.

4 0

3 years ago

Help picture attached!!

tigry1 [53]

I think it would be D, because you would divide the 1/8 be 5, giving you 1/40

6 0

3 years ago

Read 2 more answers

A population of size 320 has a proportion equal to .60 for the characteristic of interest. What are the mean and the standard de

tiny-mole [99]

Answer:

The answer is c.) 0.6 and 0.14

Step-by-step explanation:

Given population has a size of 320.

The proportion of population = 0.6

The mean of population, p = 0.6

The mean of sample, $\hat{p}$ = 0.6

Therefore $\hat{q}$ = 1 - $\hat{p}$ = 1 - 0.6 = 0.4

The sample size = 12

Therefore the standard deviation of the sample,

$s = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n} } = \sqrt{\frac{0.6 \times 0.4}{12} } = 0.1414$

The mean and the standard deviation for a sample size of 12 are 0.6 and 0.14 respectively.

The answer is c.) 0.6 and 0.14

6 0

3 years ago

Need help anyone know how to do this

Dmitry_Shevchenko [17]

X Coordinate: (-3a + 3a)/2
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Y Coordinate: (b + b)/2
2b/2 = b

Midpoint: (calculated x, calculated y)

In this case, the midpoint should be (0, b)

3 0

3 years ago

Which table shows a constant rate of change? A Days 6 12 18 Earnings ($) 225 450 750 B Days 6 12 18 Earnings ($) 225 500 750 C D

Rasek [7]

I need points sorry to do this

8 0

3 years ago