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Mariana [72]
3 years ago
12

The Green family went camping one summer. The campsite charges $65.00 a day for the space and provides food for $8.00 a person p

er day. If the Green family went camping for 5 days and spent $525, how many people are there in the Green family?
Mathematics
1 answer:
frosja888 [35]3 years ago
3 0

Answer:

5 people

Step-by-step explanation:

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3. ​Subtract 1.7 - 0.8 = _____ tenths - _____ tenths = _____ tenths = ______ what are the tenths
ANTONII [103]

Answer:

17 tenths - 8 tenths=9 tenths

Step-by-step explanation:

1.7 tenths is 17 tenths, we can see that by multiplying 1.7x10 to get 17

dot he sam with 0.8 to get 8 tenths

ti find the answer, subtract the units. 17-8=9

4 0
3 years ago
I need help with these two trigonometry problems.
telo118 [61]

Answer:

B= 21° C= 29°

Step-by-step explanation:

Use sin rule.

1st one.

sin44°/33 = sinB/17

sinB= 17sin44/33

B= sin^-1 ( ans)

B= 20,97 =21°

2nd one.

sin92°/35 = sinC/17

sinC = 17sin92°/35

C= sin^-1 (ans)

C= 29,04° = 29°

3 0
2 years ago
Expand (8h-3j)^4 <br>step by step and correct answer​
Inga [223]
Write 4 as a sum (8h-3j)^2+2
Use a m+n=a m•a n to expand the expression
(8h-3j)^2 x (8h-3j)^2
Use (a-b)^2= a^2... -2ab+b^2 to expand the expression
(64h^2 - 48hj+ 9j^2)x(64h^2 - 48hj+ 9j^2)
Multiply the parentheses and after you get your answer you collect like terms.
Your answer should be:
4096h^4 - 6144h^3j + 3456h^2j^2 - 864hj^3 +81j^4

7 0
3 years ago
a. A student builds a simple circuit with a single resistor with resistance R and measures an electric potential difference ΔV a
GrogVix [38]

Answer:

The new current is half the original current.

Step-by-step explanation:

Ohm's Law:

We use Ohm's law to solve this question. It states that

\Delta_V = RI

In which \Delta_V is the voltage difference, R is the resistence, and I is the current.

A student builds a simple circuit with a single resistor with resistance R and measures an electric potential difference ΔV across the resistor.

So

\Delta_V = RI_{1}

I_{1} = \frac{\Delta_V}{R}{/tex]Then, the student replaces the resistor with a new one of resistance 2R and keeps the electric potential difference the same.Now the current will be[tex]\Delta_V = 2RI_{2}

I_{2} = \frac{\Delta_V}{2R} = \frac{1}{2}(\frac{\Delta_V}{R}) = \frac{1}{2}(I_1)

The new current is half the original current.

7 0
3 years ago
Please help me with this problem thanks
lyudmila [28]
It should be $57.75. You have to figure out how much she earns per hour first in order to solve this problem.
3 0
4 years ago
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