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Allisa [31]
3 years ago
9

The temperature dropped from 75 degrees to 50 degrees. What was the percent decrease in the temperature?

Mathematics
2 answers:
Sav [38]3 years ago
8 0
It depends, are you talking about Fahrenheit or Celsius? Fahrenheit is simple, but Celsius is a bit complicated. The drop from 75 to 50 is 25, and 25 is one-third of 75, so that would 33% or 1/3% drop. 
jolli1 [7]3 years ago
4 0
25% is the answer because 25% of fifty is IDK
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What is the solution to the system of equations graphed below?
pentagon [3]

Answer:

C. (3,-2)

Step-by-step explanation:

5 0
3 years ago
Como se multiplican polinomios
seraphim [82]
I hope you speak english, because although i understood your question I don't know enough spanish to respond in it. You multiply polynomials by multiplying each part of one polynomial by all the other parts of the others, and then adding it all. For example: (ax+b) * (x+c) = (ax*x)+(ax*c)+(b*x)+(b*c) = a x^{2}  + acx + bx+bc

Comprehende? 
7 0
2 years ago
The table below shows the distance d(t) in feet that an object travels in t seconds: t (seconds) d(t) (feet) 2 64 4 256 6 576 8
Thepotemich [5.8K]

Answer:

128 ft/s; it represents the average speed of the object between 2 seconds and 6 seconds

Step-by-step explanation:

The average rate of change is another way to say slope.

slope = (y2-y1)/(x2-x1)

      = (576-64)/(6-2)

      = (512/4)

     =128 ft/s


This represents the change in ft per second, or the  average speed the object is going during the time period.

5 0
3 years ago
Read 2 more answers
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.0 minutes and
strojnjashka [21]

Answer:

P ( 5 < X < 10 ) = 1

Step-by-step explanation:

Given:-

- Sample size n = 49

- The sample mean u = 8.0 mins

- The sample standard deviation s = 1.3 mins

Find:-

Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.

Solution:-

- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:

                                   X ~ N ( u , s /√n )

Where

                            s /√n = 1.3 / √49 = 0.2143

- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:

                        P ( 5 < X < 10 ) = P (    (5 - 8) / 0.2143 <  Z  <  (10-8) / 0.2143   )

                                                 = P ( -14.93 < Z < 8.4 )

- Using standard Z-table we have:

                        P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1        

7 0
3 years ago
Surely help I’ll brainlist.<br><br> construct a histogram to represent these results.
AnnZ [28]

Answer:

Step-by-step explanation:

You need to first put the numbers in suitable catagories

0-120

120-130

130-140

140-150

then figure out the frequency of them

0-120=4

121-130=20

131-140=2  

141-150=2

then put in a graph(sry its not very good i was in a rush)

7 0
2 years ago
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