How To Find Inverses:
1. First, replace f(x) with y . ...
2. Replace every x with a y and replace every y with an x .
3. Solve the equation from Step 2 for y . ...
4. Replace y with f−1(x) f − 1 ( x ) . ...
5. Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.
Is that all the information? it could literally be any number with only that.
Answer: Average discharge at the mouth of the Amazon River in 1 hour = 
cubic feet
Average discharge at the mouth of the Amazon River in 1 year= 
cubic feet[/tex]
Step-by-step explanation:
Given : The average discharge at the mouth of the Amazon River =4,900,000 cubic feet per second.
i.e. The average discharge at the mouth of the Amazon River in 1 second= 4,900,000 cubic feet
Since 1 hour = 3600 seconds
Then , the average discharge at the mouth of the Amazon River in 1 hour =
cubic feet
Since , there are 2080 hours in a typical year.
Then, the average discharge at the mouth of the Amazon River in 1 year=
cubic feet
Answer:
yoo thanks u the goat
Step-by-step explanation:
Answer:
We do not have enough evidence to accept H₀
Step-by-step explanation:
Normal Distribution
size sample = n = 64 (very small sample for evaluating population of 5 years
Standard deviation 4,8
1.- Test hypothesis
H₀ null hypothesis ⇒ μ₀ = 14 and
Hₐ alternative hypothesis ⇒ μ₀ ≠ 14
2.- z(c) we assume α = 0,05 as we are dealing with a two test tail we should consider α/2 = 0.025.
From z table we the z(c) value
z(c) = 1.96 and of course by symmetry z(c) = -1.96
3.- We proceed to compute z(s)
z(s) = [ ( μ - μ₀ ) /( σ/√n) ] ⇒ z(s) = - (1.5)*√64/4.8
z(s) = - 2.5
We compare z(s) and z(c)
z(s) < z(c) -2.5 < -1.96 meaning z(s) is in the rejection zone
we reject H₀ .
From the start we indicate sample size as to small for the experiment nonetheless we found that we dont have enough evidence to accept H₀
