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miv72 [106K]
3 years ago
12

What is the distance between (-25, -3) and (1, -3)?

Mathematics
1 answer:
Virty [35]3 years ago
5 0

Answer:

3 1/2

Step-by-step explanation:

HOPE THIS HELPS SORRY FOR CAPS

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What is the best estimate for this sum 1/8+1/6=The sum will be close to?
tamaranim1 [39]

The expression given is

\frac{1}{8}+\frac{1}{6}

The sum of the expression will be,

\frac{1}{8}+\frac{1}{6}=\frac{6+8}{48}=\frac{14}{48}=\frac{7}{24}

The sum will be

\frac{7}{24}

8 0
1 year ago
5 groups of 2 hundredths =
dezoksy [38]
5x0.02=10 hope this helps! :)
7 0
3 years ago
A cylindrical jar's lid has a radius of 4 inches. If the volume is 351.68 in , approximately what is the height of the jar?
balu736 [363]

Answer:

7 inches

Step-by-step explanation:

The volume of a cylinder is calculated using

V = \pi {r}^{2}h

where r =4 inches is the radius and V=351.68 is the volume.

To find the height of the jar, we substitute these values and solve for h.

351.68 = 3.14 \times  {4}^{2}  \times h

351.68 = 50.24h

Divide both sides by 50.24 to get:

h =  \frac{351.68}{50.24}

h=7 inches

Therefore the height of the jar is 7 inches

7 0
3 years ago
Please can you help me I don't understand
Alexxx [7]
I will show you how to do the first one.....we are finding the GCF...the largest number that goes into each number (same for variables)

1.)  20yx , 80x³  ( factor each number and variable)

20  =  2, 4, 5, 10, 20
y    =  y
x     =  x
80  =  2, 4, 5, 8, 10, 16, 20, 40, 80
x³  =  x, x, x

what is the largest number that 20 and 80 have in common?    20...
how about the variables?    x

so, the Greatest Common Factor (GCF is 20x)
8 0
3 years ago
I need help with this problem
Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒cosA=\frac{u.v}{|u||v|}

Given u=-8i-3j and v=-8i+8j

|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544

|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137

let A be angle before u and v

therefore, cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}

⇒A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56

Therefore angle between u and v is 65.56°

5 0
3 years ago
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