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Liono4ka [1.6K]
3 years ago
10

Abey and Anoki are eating chocolate bars. The bars are the same size. Abey has ! 3 4 ! Left. Anoki has ! 7 8 ! Left. How much ch

ocolate is left altogether?
Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0

Answer:

13/8 of the chocolate will be left altogether.

Step-by-step explanation:

Given that,

Abey and Anoki are eating chocolate bars. The bars are the same size.

Abey left 3/4 of chocolate and Anoki left 7/8 of chocolate.

Left amount = Abey left amount + Anoki left amount

=\dfrac{3}{4}+\dfrac{7}{8}\\\\=\dfrac{3(2)+7(1)}{8}\\\\=\dfrac{6+7}{8}\\\\=\dfrac{13}{8}

Hence, 13/8 of the chocolate will be left altogether.

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Please help out guys.
Kobotan [32]

Answer:

39

Step-by-step explanation:

-\left(\left(-1\right)^2-4\right)^3-4\left(-3\right)

=-\left(-3\right)^3-4\left(-3\right)

=-\left(-27\right)-4\left(-3\right)

=-\left(-27\right)-\left(-12\right)

=39

7 0
3 years ago
What is the diameter of a tire in inches given the following data: P265/90R22 (25.4mm/ inch) a) 499 inches b) none of the other
cupoosta [38]

Answer:

d) 40.78 inches

Step-by-step explanation:

See attached for details

7 0
3 years ago
What is the greatest common multiple for 14,21
Fiesta28 [93]

Answer:

the greatest common multiple of 14 and 21 is 7.

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3 years ago
An apartment building has 35 floors with 12 apartments on each floor. There are 300 apartments that have 2 bedrooms. The rest of
Lena [83]

Answer:

120 is the answer, if we multiply 35×12= 420 apartments and there is 300 with 2 bedrooms. 420-300= 120 apartments with 1 bedroom. I hope it was helpful!

4 0
3 years ago
Find the equation of the line tangent to y = -3x2 + x - 5 at x = -1
SVEN [57.7K]

\boxed{y+9=7(x+1)}

<h2>Explanation:</h2>

The Point-Slope form of the equation of a line is given by:

y-y_{0}=m(x-x_{0}) \\ \\ \\ Where: \\ \\ m:Slope \\ \\ (x_{0},y_{0}):A \ point

To find the equation of the line tangent to y=-3x^2+x-5 \ at \ x=-1, we need to take the derivative:

\frac{dy}{dx}=-6x+ 1

The slope of the line tangent to y=-3x^2+x-5 at x=-1 can be found evaluationg x=1 in the derivative:

\frac{dy}{dx}\Bigr\rvert_{x=-1}=-6x+ 1 \\ \\ \\ \frac{dy}{dx}\Bigr\rvert_{x=-1}=-6(-1)+ 1 \\ \\ \\  m=\frac{dy}{dx}\Bigr\rvert_{x=-1}=7

Finding the point:

x_{0}=-1 \\ \\ Then: \\ \\ y_{0}=-3(-1)^2-1-5=-9 \\ \\ (x_{0},y_{0})=(-1,-9)

Finally, our line is:

y-(-9)=7(x-(-1)) \\ \\ \boxed{y+9=7(x+1)}

The representation of this problem is shown below.

<h2>Learn more:</h2>

Derivative of functions: brainly.com/question/2142425

#LearnWithBrainly

6 0
3 years ago
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