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IgorLugansk [536]
3 years ago
15

What is the diameter of a tire in inches given the following data: P265/90R22 (25.4mm/ inch) a) 499 inches b) none of the other

choices c) 31.39 d) 40.78 inches

Mathematics
1 answer:
cupoosta [38]3 years ago
7 0

Answer:

d) 40.78 inches

Step-by-step explanation:

See attached for details

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Find the value of x. Plz hurry
WITCHER [35]

Answer:

x = 12

Step-by-step explanation:

both (x+5) and (2x-7) are corresponding angles formed by an intersection between a transversal and 2 parallel lines.

hence they are equal in value

x+5 = 2x-7

x - 2x = -7 - 5

-x = -12

x = 12

5 0
3 years ago
Chloe has $45 in her bank account. After she went
arsen [322]

Answer:

45-12=33

Step-by-step explanation:

you subtract 45 by 12 and get 33

8 0
4 years ago
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White raven [17]

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3 years ago
Please help. quickly if possible
Dafna11 [192]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
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Resolve into partial fraction. (5x+2)/3x²+4x-4​
gladu [14]

Answer:

\frac{5x+2}{3x^2+4x-4}= \frac{2}{3x-2}+\frac{1}{x+2}

Step-by-step explanation:

Ooook, step 1: write the denominator as a product, or we're not going anywhere. Can't spot any two factor by staring at it, so quadratic formula it is.

x= \frac13(-2 \pm \sqrt{4+12})=\frac13(-2\pm4) = -2;\frac23

We got our toots, let's split the denominator now: 3x^2+4x-4 = (3x-2)(x+2)\\

Now it's all a matter of writing down what we need:

\frac{5x-2}{3x^2+4x-4}=\frac{5x-2}{(3x-2)(x+2)} = \frac{A}{3x-2}+\frac{B}{x+2} = \frac{A(x+2)+B(3x-2)}{(3x-2)(x+2)}=\frac{Ax+2A+3Bx-2B}{(3x-2)(x+2)} =\frac{(A+3B)x+(2A-2B)}{(3x-2)(x+2)}

Here comes the fun part. Two ways: the fast and loose, and the long one.

<u>Fast and loose</u>: let's look only at the numerators of the 3rd to last and first step: A(x+2)+B(3x-2) = 5x+2 If we plugged a convenient value, let's say x=-2 the coeffcent of A would disappear, and we would be able to find B. Let's do it. A(-2+2) + B(3(-2)-2) = 5(-2)+2 \rightarrow -8B =-8 B=1

At this point we have B, let's pick a different value of x, let's say 1, to get A:

A(3) + 1(1) = 7 \rightarrow 3A=6 \rightarrow A=2

<u>More traditional: </u>Pick the first and last numerators: 5x+2 = (A+3B)x+(2A-2B). Stare at them long enough and pick your favourite excuse to justify the following system (two polynomials are equal if the coefficents are equal, polynomials create a vector space of base (1,x,x^2...)

\left \{ {A+3B=5} \atop {2A-2B=2}} \right.

Again, A=2, B=1 is a solution.

Either way, the solution is:

\frac{5x+2}{3x^2+4x-4}= \frac{2}{3x-2}+\frac{1}{x+2}

6 0
3 years ago
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