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gladu [14]
3 years ago
9

Rewrite the slope in intercept form.x-3y=15​

Mathematics
2 answers:
Dima020 [189]3 years ago
5 0

Answer:

x=3y+15

Step-by-step explanation:

Bumek [7]3 years ago
5 0
X-3y = 15

-3y = 15-x

y = -5 + ¹/₃x
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What is the value of the interquartile range of the dea below?<br><br> 4 5 8 13
Lunna [17]
So first you have to find the median, to do this you use the formula (n+1)/2 with n being how many numbers there are.
As there are 4 numbers we can substitute it into the formula to make (4+1)/2 which is 2.5
Then you find the 2nd place and the 3rd place (which are 5 and 8) and find exactly the middle of them which is 6.5 (the median)

To find the lower quartile we take the 2.5 from earlier and divide it by 2 to make 1.25 so we find where that place is in the number. 4 is the first place and then we find what 1/4 is and add that on to make 4.25 which is the lower quartile.

Then you do 2.5+1.25 to find the upper quartile to make 3.75 so we find where that is in the numbers which is in-between 8 and 13 so it will be 8+1.22 to make 9.22

So to find the interquartile range you do the upper quartile takeaway the lower quartile so 9.22-4.25 which is 4.97 and that is the answer
5 0
3 years ago
Read 2 more answers
If y varies inversely as x and y=3 when x=8 what is x when y=4
I am Lyosha [343]

Answer:

x = 6

Step-by-step explanation:

y varies inversely as x

y = k × 1/x. {where k is a constant}

when y = 3, x = 8

Therefore 3 = k/8 and k is 24

y = 24/x

When y = 4,

4 = 24/x

4x = 24

(dividing both sides by 4)

x = 6

5 0
3 years ago
A student received a 76% on an exam. If there were 20 questions on the exam, which ratio would show the number of questions answ
cestrela7 [59]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A university offers 3 calculus classes: Math 2A, 2B and 2C. In both parts, you are given data about a group of students who have
ankoles [38]

Answer:

4 students

Step-by-step explanation:

The total number of students is given by:

|A|+|B|+|C|-|A\cap B|-|A\cap C|-|B\cap C| + |A\cap B \cap C| = N

Where N is the total number of students, A is the number of students that have taken Math 2A, B is the number of students that have taken Math 2B, and C is the number of students that have taken Math 2C:

|A|+|B|+|C|-|A\cap B|-|A\cap C|-|B\cap C| + |A\cap B \cap C| = N\\51+80+70-15-20-13 +  |A\cap B \cap C|  = 157\\ |A\cap B \cap C| =4

4 students in Group A have taken all three classes.

*The number of students that have taken two classes has be subtracted so those students do not get counted twice

4 0
4 years ago
Write -1/6, 5/3, -5/6 in order from least to greatest
mash [69]
The easiest way to compare fraction is to make them all have the same denominator and then you can just compare the numerators...

-1/6, (5/3)(2/2), -5/6

-1/6, 10/6, -5/6  so from least to greatest

-5/6, -1/6, 10/6

-5/6, -1/6, 5/3
5 0
3 years ago
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