Answer:
51.32
Step-by-step explanation:
∠B = arcsin(b·sin(A)a)
= 0.67513 rad = 38.682° = 38°40'56"
∠C = 180° - A - B = 0.89566 rad = 51.318° = 51°19'4"
c = a·sin(C)sin(A) = 31.22499
12 for $25 is $2.08 per each. 24 for $46 is $1.90 per each. 50 for $94 is $1.90 per each.
Answer:
6f = 24
f = 4
Step-by-step explanation:
Answer:
a=8.06
A=29.74
B=60.26
Step-by-step explanation:
This is a right angled triangle and Pythagoras theorem is to be obeyed.
To get c, we follow the Pythagoras rule that says
Hyp² = Opp² + Adj²
c= Hypotenuse
c²= a² + b²
c² = 4² + 7²
c² = 65
c = √65 = 8.06
For angle A,
the opposing side to the angle = a = 4
The adjacent side to the angle = b = 7
Following trigonometry rule.
Tan A = opp/adj
Tan A = 4/7
A = Tan–¹(4/7)
A = 29.74°
For angle B,
Opposing side = 7
Adjacent side = 4
Tan B = 7/4
B = Tan-¹(7/4)
B = 60.26°
The weight average of the coordinates is -4
<h3>How to determine the
weight average?</h3>
The complete question is given as:
The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. And we need to calculate the weight average
The given parameters are:
- Coordinate -6 has a weight of 3
- Coordinate 2 has a weight of 1.
The weight average is then calculated as:
Weight average = Sum of (Weigh * Coordinate)/Sum of Weights
So, we have:
Weight average = (-6 * 3 + 2 * 1)/(3 +1)
Evaluate the products
Weight average = (-18 + 2)/(3 +1)
Evaluate the sum
Weight average = -16/4
Evaluate the quotient
Weight average = -4
Hence, the weight average of the coordinates is -4
Read more about average at
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<u>Complete question</u>
The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. Calculate the weight average
