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Inessa [10]
3 years ago
6

Simplify 8/10 please help me

Mathematics
1 answer:
Daniel [21]3 years ago
6 0
Well to simplify 8/10 you divide by 2 for both numbers on top and bottom like this 8/10 divided by 2 would equal to 4/5 the answer will be 4/5
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Justo ayer fue el cumpleaños de Mauricio. Si a la edad e Mauricio, le sumo 13, al resultado le resto 10, luego al nuevo resultad
bezimeni [28]

Answer:

Mauricio nació en el año 2000.

Step-by-step explanation:

Supóngase que el cumpleaños se celebra en el año 2020, si x es la edad actual de Mauricio, entonces la expresión matemática que traduce el enunciado del problema es:

\frac{(x+13)-10}{23} +20 = 21

Ahora, se desarrolla y se simplifica la ecuación:

\frac{x+3}{23}+20 = 21

\frac{x+3}{23} = 1

Se despeja x:

x +3 = 23

x = 20

Mauricio tiene 20 años.

Ahora, el año de nacimiento de Mauricio es la sustracción de la edad de Mauricio del año actual:

y = 2020-20

y = 2000

Mauricio nació en el año 2000.

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3 years ago
Write an equation in point-slope form for the line through the given point with the given slope.
Thepotemich [5.8K]

Answer: A

Step-by-step explanation:

3 0
3 years ago
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
What is the product of (x+2) (x-4)
skelet666 [1.2K]
(x + 2)(x - 4)

= x^2 + 2x - 4x - 8
= x^2 - 2x - 8
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3 years ago
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hichkok12 [17]

Answer:

-66/7

Step-by-step explanation:

1/3x-11=3/2x

2/6x-11=9/6x

7/6x=-11

x=-66/7

5 0
3 years ago
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