Here is the highly detailed, arcane, complex, technical form of Ohm's Law that is needed in order to answer this question ===> V = I · R .
Voltage = (current) x (resistance)
Voltage = (2 Ampere) x (8 Ω)
<em>Voltage = 16 volts</em>
When its tangential speed is constant
<span>Although the speed of an object that has a uniform circular motion is constant, its velocity is </span>not constant<span>. Not only that, but it is actually changing constantly.</span><span>
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Answer:
the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15
Explanation:
Given that;
speed of car V = 120 km/h = 33.3333 m/s
Reaction time of an alert driver = 0.8 sec
Reaction time of an alert driver = 3 sec
extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec
now, extra distance that car will travel in case of sleepy driver will be'
S_d = V × 2.2 sec
S_d = 33.3333 m/s × 2.2 sec
S_d = 73.3333 m
hence, number of car of additional car length n will be;
n = S_n / car length
n = 73.3333 m / 5m
n = 14.666 ≈ 15
Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15
When two sound waves of different frequencies approach the ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - producing beats
