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Contact [7]
2 years ago
8

15 Points , Physics HW, can someone please show me step by step how to calculate percent difference for this problem. My numbers

are listed in the image. Thank you so much!

Physics
1 answer:
timofeeve [1]2 years ago
3 0

The percent difference between two numbers x and y is given by

\dfrac{|y-x|}x \times 100\%

The absolute value is there because we only care about the absolute percent difference, and not taking into account whether we go from x to y or vice versa. If we remove them, we have two possible interpretations of percent difference.

For example, the (absolute) percent difference between 3 and 6 is

\dfrac{|6-3|}3 \times 100\% = 100\%

In other words, we add 100% of 3 to 3 to end up with 6. This is the same as the percent difference going from 3 to 6. On the other hand, the percent difference going from 6 to 3 is

\dfrac{3-6}3\times100\%=-50\%

which is to say, we take away 50% of 6 away from 6 to end up with 3.

"Make comparisons to object measurements" tells us that the differences should be computed relative to "measurements for object". In other words, take x from the left column and y from the right column.

\dfrac{|7.1-7.3|}{7.1} \times 100\% \approx 2.82\%

\dfrac{|4.8-5.0|}{4.8} \times 100\% \approx 4.17\%

\dfrac{|7.2-7.5|}{7.2} \times 100\% \approx 4.17\%

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Car B is rounding the curve with a constant speed of 54 km/h, and car A is approaching car B in the intersection with a constant
levacccp [35]

This question is incomplete, the complete question is;

Car B is rounding the curve with a constant speed of 54 km/h, and car A is approaching car B in the intersection with a constant speed of 72 km/h. The x-y axes are attached to car B. The distance separating the two cars at the instant depicted is 40 m. Determine: the angular velocity of Bxy rotating frame (ω).

Answer:

the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s

Explanation:

Given the data in the question and image below and as illustrated in the second image;

distance S = 40 m

V_B = 54 km/hr

V_A = 72 km/hr

α = 100 m

now, angular velocity of Bxy will be;

ω_B = V_B / α

so, we substitute

ω_B = ( 54 × 1000/3600) / 100

ω_B = 15 / 100

ω_B = 0.15 rad/s

Therefore, the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s

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3 years ago
What is always coming, but never arrives?
nataly862011 [7]

Answer:Tommorow

Explanation:

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3 years ago
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The design phase in which a building project's basic functional requirements are first laid out (square footage, utility and equ
VikaD [51]

Answer:

e. design programming

Explanation:

The planning techniques are responsible for structuring the tasks to be performed within the project, defining the duration and the order of execution of the same, while the programming techniques try to organize the activities so that the logical temporal relationships between them, determining the calendar or the moments of time in which each one must be realized. The programming must be consistent with the objectives pursued and respect existing restrictions (resources, costs, workloads).

The programming therefore consists in setting, in an approximate way, the moments of beginning and termination of each activity. Some activities may have slack and others are critical activities (fixed over time).

STEPS:

Build a time diagram (moments of beginning and slack of activities).

Establish the times of each activity.

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3 years ago
3. What is the gravitational force between a 70 kg physics student and her 1 kg textbook, at a distance of 1 meter? (This number
Rina8888 [55]

ANSWER

\begin{equation*} 4.67*10^{-9}\text{ }N \end{equation*}

EXPLANATION

Parameters given:

Mass of the student, M = 70 kg

Mass of the textbook, m = 1 kg

Distance, r = 1 m

To find the gravitational force acting between the student and the textbook, apply the formula for gravitational force:

F=\frac{GMm}{r^2}

where G = gravitational constant

Therefore, the gravitational force acting between the student and the textbook is:

\begin{gathered} F=\frac{6.67430*10^{-11}*70*1}{1^2} \\  \\ F=4.67*10^{-9}\text{ }N \end{gathered}

That is the answer.

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1 year ago
Make the following conversion. 0.0097 mg = _____ g
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Your answer should be 9.7 :)
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