Answer:
in left
Explanation:
Hope it will help
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Answer:
As a type of thermal power station, a coal-fired power station converts chemical energy stored in coal successively into thermal energy, mechanical energy and, finally, electrical energy. The coal is usually pulverized and then burned in a pulverized coal-fired boiler.Coal-fired plants produce electricity by burning coal in a boiler to produce steam. The steam produced, under tremendous pressure, flows into a turbine, which spins a generator to create electricity.
Given:
Gasoline pumping rate, R = 5.64 x 10⁻² kg/s
Density of gasoline, D = 735 kg/m³
Radius of fuel line, r = 3.43 x 10⁻³ m
Calculate the cross sectional area of the fuel line.
A = πr² = π(3.43 x 10⁻³ m)² = 3.6961 x 10⁻⁵ m²
Let v = speed of pumping the gasoline, m/s
Then the mass flow rate is
M = AvD = (3.6961 x 10⁻⁵ m²)*(v m/s)*(735 kg/m³) = 0.027166v kg/s
The gasoline pumping rate is given as 5.64 x 10⁻² kg/s, therefore
0.027166v = 0.0564
v = 2.076 m/s
Answer: 2.076 m/s
The gasoline moves through the fuel line at 2.076 m/s.
displacement is given by equation
now at t = 5 s the position is
similarly position at t = 9 s
so the displacement of object in given interval of time will be
time interval
now the average velocity will be given as
so its average speed is 252 m/s
Answer:
1.08x10⁻⁷
Explanation:
F=(GM₁M₂)/r²
=((6.67x10⁻¹¹)(70)(52))/(1.5²)
=2.42788x10⁻⁷/2.25
=1.07905778x10⁻⁷
≈1.08x10⁻⁷
