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maxonik [38]
3 years ago
13

A survey of 100 families showed that 35 had a dog: 28 had a cat: 10 had a dog and a cat: 42 had neither a cat nor a dog nor a pa

rakeet: 0 had a cat, a dog, and a parakeet. How many had a parakeet only? A. 20 B. 15 C. 5 D. 10

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0
<h2>Answer:</h2>

Option: C is the correct answer.

                    C.    5

<h2>Step-by-step explanation:</h2>

We will solve the following problem with the help of the Venn diagram.

Based on the Venn diagram we are asked to find the value of v i.e. those who have parakeet only.

From the information that:

  • 35 had a dog  we have:

          x+y+10=35

              i.e.

                x+y=25

Also, based on the information :

  • 28 had a cat we have:

                  u+z+10=28

                   i.e.

                  u+z=18

Also, 42 had neither a cat nor a dog nor a parakeet.

 This means it cover the outer region of the three circles.

Total 100 families were surveyed it means that:

        42+x+y+10+u+z+v=100

i.e.       42+25+10+18+v=100

i.e.         95+v=100

i.e.           v=100-95

i.e.           v=5    

Hence, the number of families who have only parakeet are:  5

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Answer:

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7 0
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What is negative 2 plus positive two (-2+2) ????
dmitriy555 [2]

Answer:

A_ 1,2,4,5,-1, or,-2

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2+(-2)

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Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Assume that all conditions are met. The mean of the differences was 1. 33 and the standard deviation of those differences was 2.
Maurinko [17]

The test statistic for this procedure is using two sample T-test is 0.458.

Definition of Two Sample T-test

A variation of the Student's t-test used to determine if two sample means are substantially different is known as the two sample T-test (also known as Welch's t-test, Welch's adjusted T, or unequal variances t-test). The test's degrees of freedom have been changed, which generally boosts the test's power for samples with unequal variance.

T-Test Statistic for The Procedure

It is given that mean of the differences = 1.33

And, the standard deviation of the differences, standard error = 2.90

The test static formula is given as,

t = (estimate - hypothized value) / standard error

Here,  t is the t- test statistic, and estimate is the mean of the differences.

Since it is given that all conditions are met, the hypothized value can be taken as 0

Substituting substituting estimate = 1.33 and standard error = 2.90 in the t-test statistic formula, we get,

t = (1.33-0)/2.90

or t = 0.458

learn more about t-test here:

brainly.com/question/14128303

#SPJ4

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John answered 80% of the questions correctly. There were 30 questions on the test. How many questions did John answer correctly?
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Answer:

he got 24 right

Step-by-step explanation:

30 time 80% is 24

7 0
3 years ago
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