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leva [86]
2 years ago
12

inspection of a random sample of 25 aircraft showed that 17 needed repairs to fix a wiring problem that might compromise safety.

(a) how large a sample would be needed to estimate the true proportion of jets with the wiring problem, with 90 percent confidence and an error of ± 5 percent?
Mathematics
1 answer:
lora16 [44]2 years ago
6 0

   The random sample proportion:  

 at 90% confidence interval: The Central 90% of any normal   distribution is: Z_(α/2) = 1.960

   Error = E = ±5% = ±0.05

   Applying the normal distribution theory,

= 0.70 ≤ P≤  0.77(this means that we are 90% confident that the true proportion of jet with wiring problem fall with 0.70 and 0.77, hence there is no need for the airline to conduct further sampling, rather, they should just inspect all the planes)

learn more about probability: brainly.com/question/13604758

21234

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Solve using the elimination method:<br> X-3y=7<br> 3x + 3y=9
sergij07 [2.7K]

Answer:

                        x=4\\\\y=-1

Step-by-step explanation:

Given Equation:

x-3y=7      Equation:1

3x + 3y=9     Equation:2

Dividing Equation:2 by '3' both the sides:

x+y=3      

or   x=3-y     Equation:3

Putting the vale of 'x' in Equation:1

                             x-3y=7

                          (3-y)-3y=7\\\\3-y-3y=7\\\\3-4y=7\\\\

Subtracting '3' both sides

                             -4y=7-3\\\\-4y=4

                                 y=\frac{4}{-4}

                                 y=-1

Putting value of 'y' in Equation:3

                                x=3-y

                                x=3-(-1)\\\\x=3+1\\\\x=4

The solution of the equations is :

                              x=4\\\\y=-1

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6 0
3 years ago
What is the equation of M=3,x=4,and b=9
natita [175]

Answer:

21=3(4)+9

Step-by-step explanation:

Assuming that the equation that you are trying the get is y=mx+b, plug in m, x, and b to get:

y=3(4)+9

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y=21

Please be more specific so that you get the answer you need

6 0
4 years ago
Ann has 30% less money than Mary, and Jessica has 70% more than Mary. If the 3 of them have a (added up) total of $102, how much
Roman55 [17]
Let x be the amount of Ann money, y be Jessica's money and z Mary money. 
30% of z equates 0.3*z. 
Ann has 30% less than z so: x = z - 0.3z = 0.7z.
70% of z equates 0.7z. 
"Jessica has 70% more than Mary " we deduce the equation: y =z+0.7z= 1.7z.
Signe the total is $102, we deduce the equation x+y+z = 102. 
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x=0.7*30= 21 and y=1.7*30=51.

Ann has $21, Mary has $30 and Jessica has $51.
  
3 0
4 years ago
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