The function c(x) = 18x -10 represents the cost in dollars. How many tickets can you buy?

Mathematics

1 answer:

Natalija [7]3 years ago

8 0

Note: It seems you may have unintentionally missed writing the complete question. As total cost is missing.

So, I am assuming how many tickets Mr. XYZ can buy if he/she pays 98 dollars.

The solution would still clear your concept though.

Answer:

Please check the explanation.

Step-by-step explanation:

We know that the slope-intercept form of the line equation

y = mx+b

where m is the slope and b is the y-intercept

Given the function

c(x) = 18x -10

comparing with the slope-intercept form of the line equation

rate of change = slope = m = 18

c(x) or y represents the cost

According to the function equation,

'x' represents the number of tickets

Assuming the total cost i.e. c(x) = $98

In order to determine the value of x, set c(x) = 98

i.e.

98 = 18x -10

switch sides

18x - 10 = 98

add 10 to both sides

18x - 10 + 10 = 98 + 10

18x = 108

Divide 18 to both sides

18x/18 = 108/18

x = 6

Therefore, if you can buy x = 6 if you pay 98 dollars.

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In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

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Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

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The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$