Answer:
<u>k = 3</u>
Step-by-step explanation:
one zero of p(x) = kx²– 14 x + 8 is 6 times the other.
let the zeros are ⇒ a and 6a
the equation kx²– 14 x + 8
can be written as k ( x²/k– 14/k x + 8/k)
So, a * 6a = 8/k ⇒ (1)
And a + 6a = 14/k ⇒ (2)
from (2) k = 14/(a + 6a) = 14/(7a) = 2/a
∴ a = 2/k
Substitute at (1)
a * 6a = 8/k
2/k * 12/k = 8/k
solve for k
24/k = 8
k = 24/8 = 3
<u>the value of k = 3</u>
And the zeros will be 2/3 and 4
