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Scorpion4ik [409]
3 years ago
7

Find the value of ‘k’ if one zero of p(x) = kx2 – 14 x + 8 is 6 times the other.

Mathematics
1 answer:
Finger [1]3 years ago
5 0

Answer:

<u>k = 3</u>

Step-by-step explanation:

one zero of p(x) = kx²– 14 x + 8 is 6 times the other.

let the zeros are ⇒ a and 6a

the equation kx²– 14 x + 8

can be written as k ( x²/k– 14/k x + 8/k)

So, a * 6a = 8/k    ⇒ (1)

And a + 6a = 14/k ⇒ (2)

from (2)  k = 14/(a + 6a) = 14/(7a) = 2/a

∴ a = 2/k

Substitute at (1)

a * 6a = 8/k

2/k * 12/k = 8/k

solve for k

24/k = 8

k = 24/8 = 3

<u>the value of k = 3</u>

And the zeros will be 2/3 and 4

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