Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
Answer:
tttt5556689
Step-by-step explanation:
hehe
Answer:
J. -13-18
Step-by-step explanation:
J will give the value -31
Answer:
true
Step-by-step explanation:
Answer:
Below
Step-by-step explanation:
You can use this formula to find the sum of an arithmetic series
Sn = n / 2 (a1 + an)
You need to find the number of terms in each series before using the formula
Tn = a + (n - 1) d
a) 53 = 5 + (n - 1) 3
n = 17
Sn = 17 / 2 (5 + 53)
= 493
b) 98 = 7 + (n - 1) 7
n = 14
Sn = 14 / 2 (7 + 98)
= 735
c) -102 = 8 + (n - 1) -5
n = 23
Sn = 23 / 2 (8 + (-102))
= - 1081
d) 41/3 = 2/3 + (n - 1) 1
n = 14
Sn = 14 / 2 (2/3 + 41/3)
= 301 / 3 or 100 1/3
Hope this helped! Best of luck <3
