And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

3 years ago

Sam evaluated the expression x2y for x = 7 and y = 9. He got a value of 49. which of the follwing statements is correct

Marrrta [24]

<span>B. sam forgot to multiply.
The correct answer is
</span> x^2*y=(7^<span>2)*(9)=49*9=441 </span>

7 0

3 years ago

Which is bigger 2.0 or 2

alekssr [168]

Answer:

both are the same

Step-by-step explanation:

2.0 = 2

hope this helps ^-^

4 0

3 years ago

Read 2 more answers

Can someone please help me on this ASAP!

kondaur [170]

Answer:

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6 0

3 years ago