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3 years ago

Which equation solves the real world problem below?

Mathematics

1 answer:

posledela3 years ago

3 0

Answer:

d) 3 1/4

Step-by-step explanation:

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If sin(t) = 3/5 and t is in the 2nd quadrant, find cos(t).

NemiM [27]

Cosine is $\frac{hypotenuse}{adjacent}$ .

Apply the equation:

$sin(t) = \frac{3}{5} \\3^2 + b^2 = 5^2\\b^2 = 5^2 - 3^2\\\\\sqrt{b^2} = \sqrt{5^2}- \sqrt{3^2}\\\\\\b = 5 - 3 \\\\b = 2$

B is the adjacent side so

cosine is:

Cos(t) = 5/2

Have a great day,

And I hope this helps you!

5 0

2 years ago

The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in <em>fourth</em> quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in <em>4th quadrant </em>so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

6 0

3 years ago

Sally has 14 diamonds and she puts 6 in the ground how many more diamonds does sally have?

Marina86 [1]

Answer:

Sally would have 8 diamonds left

5 0

3 years ago

Which of the sets of ordered pairs represents a function?

alexandr1967 [171]

Answer:

The correct option is 4. Neither A nor B represents a function.

Step-by-step explanation:

The given sets of ordered pairs are

$A=\{(1,-5), (8,-5), (8,7), (2,9)\}$

$B=\{(7,-4), (7,-2), (6,-3), (-9,5)\}$

A set of ordered pairs represents a function if there exist unique outputs for all inputs. It means for each values of x there exist, a unique value of y.

In set A the value of y-coordinates are -5 and 7 at $x=8$ .