Answer:
0.1587
Step-by-step explanation:
Let X be the commuting time for the student. We know that 
. Then, the normal probability density function for the random variable X is given by
![f(x) = \frac{1}{\sqrt{2\pi(5)^{2}}}\exp[-\frac{(x-\mu)^{2}}{2(5)^{2}}]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%5Cpi%285%29%5E%7B2%7D%7D%7D%5Cexp%5B-%5Cfrac%7B%28x-%5Cmu%29%5E%7B2%7D%7D%7B2%285%29%5E%7B2%7D%7D%5D)
. We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,
= 0.1587
To find this probability you can use either a table from a book or a programming language. We have used the R statistical programming language an the instruction pnorm(35, mean = 30, sd = 5, lower.tail = F)
Find the horizontal and vertical distance between the points. First, subtract y2 - y1 to find the vertical distance. Then, subtract x2 - x1 to find the horizontal distance.
The answer is 96, don't ask how, just know.
Answer:
9 bags
Step-by-step explanation:
First we will need to calculate the area of their entire backyard, which has a shape of trapezium.
So the formula for the area of a trapezium is 
a and b are the lenghts of the parallel sides and h is the height.
From the picture 
Then we plug into our formula
square feet
To get the number of bags required we just simply divide the aree of their entire yard by the space that 1 bag covers. We get:
bags
This is more than 8 bags so they will need 9 bags to cover their entire yard.
The shape of the cross-section formed is a triangle, when a cone is cut in such a way that the cross-section is perpendicular to the base and it passes through the vertex.
