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Oksana_A [137]
3 years ago
13

Please help me answer this question!!!!

Mathematics
1 answer:
kotykmax [81]3 years ago
3 0

9514 1404 393

Answer:

  y = 4x +3

Step-by-step explanation:

The slope formula can be used to find the slope:

  m = (y2 -y1)/(x2 -x1)

Using the first two lines of the table, we find the slope to be ...

  m = (11 -7)/(2 -1) = 4/1 = 4

__

The y-intercept can be found from the relation ...

  b = y -mx

Using the slope we found, and the first line of the table, we find the intercept to be ...

  b = 7 -4(1) = 3

__

Then the equation is ...

  y = mx +b . . . . . . slope-intercept form of the equation for a line

  y = 4x +3

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150+55w

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150+55w

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HACTEHA [7]

Answer:

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Step-by-step explanation:

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Solve the following equation by completing the square. 3x^2-3x-5=13
mr Goodwill [35]

we'll start off by grouping some

\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}

6 0
3 years ago
Simplify this (2x)^{3}
Margaret [11]

Answer:

8x^3

Step-by-step explanation:

(2x)3

=(2x)3

=2x*2x*2x

=8x^3

7 0
3 years ago
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