Answer:
each gift =$10
total=y
number of gifts =x
therefore,total= each gift * number of gifts
=$10* x
Complete Question
The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?
Answer:
The value is
Step-by-step explanation:
From the question we are told that
The rate at which fire breaks out every 10 years is
Generally the probability distribution function for Poisson distribution is mathematically represented as
Here x represent the number of state which is 2 i.e
Generally the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as
=>
=>
=>
=>
=>
Answer:
12
Step-by-step explanation:
divided 16 by 4 which is 4. then multiply 2 by 6, which is 12. then multiply 4 by 12. Remember to always do ( ) first. 4 by 12 is 48. Then do 48 divided by 6 which is 8. then add 8+4 which is 12.
Answer:
...........the answer is 7?!
Answer:
Therefore, the budget is 656.76$.
Step-by-step explanation:
We know that a lab orders a shipment of 100 rats a week for experiments that the lab conducts. Suppose the mean cost of the rats turned out to be $ 12.63 per week. We calculate budget of a lab for the next year's.
We know that 1 year have 52 weeks. We get
52 · 12.63 = 656.76
Therefore, the budget is 656.76$.