Cost of two tickets that Sheila paid to her friend = $ 90
Actual price of 1 ticket = $ 52.50
So, actual price of 2 tickets = 52 x 2 = 105
Hence, markdown or discount Sheila's friend gave her is =
105 - 90 = 15
The answer is $15.
The radius is 4.99, im sure
We are given a function f ( x ) defined as follows:
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We are to determine the value of f ( x ) when,
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In such cases, we plug in/substitue the given value of x into the expressed function f ( x ) as follows:
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We will apply the power on both numerator and denominator as follows:

Now we evaluate ( 2 ) raised to the power of ( 1 / 9 ).
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Next apply the division operation as follows:

Once, we have evaluated the answer in decimal form ( 5 decimal places ). We will round off the answer to nearest thousandths.
Rounding off to nearest thousandth means we consider the thousandth decimal place ( 3rd ). Then we have the choice of either truncating the decimal places ( 4th and onwards ). The truncation only occurs when (4th decimal place) is < 5.
However, since the (4th decimal place) = 8 > 5. Then we add ( 1 ) to the 3rd decimal place and truncate the rest of the decimal places i.e ( 4th and onwards ).
The answer to f ( 1 / 2 ) to the nearest thousandth would be:

No. i*i = -1
2i*3i=-6
now if they meant complex numbers the answer is still no
(2+4i)(2-4i) = 4-8i+8i-16 = -12
Answer:
a) 0.0002
b) 0.0057
c) 0.0364
Step-by-step explanation:
Lets start by stating the probabilities of a person belonging to each policy:
Standard: 0.3
Preferred: 0.5
Ultra- Preferred: 0.2
The probability of person belonging to each policy AND dying in the next year:
Standard: 0.3 x 0.015 = 0.0045
Preferred: 0.5 x 0.002 = 0.001
Ultra- Preferred: 0.2 x 0.001 = 0.0002
a) The probability a ultra - preferred policy holder dies in the next year is 0.001. To find the probability of a person being both a ultra - preferred policy holder AND die in the next year is: 0.001 x 0.2= 0.0002
b) The probability is given by adding the probabilities calculated before :
0.0045 + 0.001 + 0.0002 = 0.0057
c) We use the results above again. This is 0.0002 / (0.001 + 0.0045). The answer comes out to be 0.0364