Answer:
The probability will be "0.0111".
Step-by-step explanation:
The given values are:
Mean,
= 79
Standard deviation,
= 3.5
Now,
⇒ 
⇒ 
So,
= ![1 - P{\frac{(\bar x - \mu \bar x )}{ \sigma \bar x} < \frac{(81 - 79) }{0.875} ]](https://tex.z-dn.net/?f=1%20-%20P%7B%5Cfrac%7B%28%5Cbar%20x%20-%20%5Cmu%20%5Cbar%20x%20%29%7D%7B%20%5Csigma%20%5Cbar%20x%7D%20%20%3C%20%5Cfrac%7B%2881%20-%2079%29%20%7D%7B0.875%7D%20%5D)
= 
= 
Answer:
$6.50 per bag of popcorn
Step-by-step explanation:
let a bag of popcorn be represented by p and a candy bar be b
28p + 40b= $282
17p + 20b= $160.50
this is an example of stimatanelous equations
so you have to double the second equation to give 34p + 40b =$321
subtract the equations to give one
6p =$39
divide $39 by 6 to give the value of one bag of popcorn = $6.50
When you multipy 1.229 x 15 your answer is 18.435. Rounding to the nearest cent will only include 2 numbers after the decimal. Looking at 18.435, the last number, 5 will round your answer to 18.44
Answer: the probability that a randomly selected tire will have a life of exactly 47,500 miles is 0.067
Step-by-step explanation:
Since the life expectancy of a particular brand of tire is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = life expectancy of the brand of tire in miles.
µ = mean
σ = standard deviation
From the information given,
µ = 40000 miles
σ = 5000 miles
The probability that a randomly selected tire will have a life of exactly 47,500 miles
P(x = 47500)
For x = 47500,
z = (40000 - 47500)/5000 = - 1.5
Looking at the normal distribution table, the probability corresponding to the z score is 0.067
6 ribbons
1/4 yard long each
4 yards= 4 ribbons
4/4 yards
A: 6/4 Yards
