Y-99=-1/33(x-22)
a). y = 1/33x + 98 1/3
b) 33y = x + 109 1/3
x - 33y = -109 1/3
Answer:
7:25 P.M.
Step-by-step explanation:
Add 2:25, 1:25, and 2:40 = 6:30 and add that to 12:55= 19:25 which is also equal to 7:25 P.M.
Answer: y= -5x
Step-by-step explanation:
intercept form is y=mx+b
we have the x, I guess we can also call it the rate of change
they gave us a point (3,0), we see the 0 is in the y place making it the b, now just plug it in, since its 0 we can leave it blank
They will each spend 40.94$ but all together they spent 204.70$ Hope I helped;)
![f(x)=(1-x^2)^{\frac{2}{3}}\implies \cfrac{df}{dx}=\cfrac{2}{3}(1-x^2)^{-\frac{1}{3}}\implies \cfrac{df}{dx}=\cfrac{2}{3\sqrt[3]{1-x^2}}](https://tex.z-dn.net/?f=f%28x%29%3D%281-x%5E2%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7Bdf%7D%7Bdx%7D%3D%5Ccfrac%7B2%7D%7B3%7D%281-x%5E2%29%5E%7B-%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7Bdf%7D%7Bdx%7D%3D%5Ccfrac%7B2%7D%7B3%5Csqrt%5B3%5D%7B1-x%5E2%7D%7D)
when it comes to a rational expression, we can get critical points from, zeroing the derivative "and" from zeroing the denominator alone, however the denominator provides critical valid points that are either "asymptotic" or "cuspics", namely that the function is not differentiable or not a "smooth line" at such spot.
if we get the critical points from the denominator on this one, we get x = ±1, both of which are cuspics. Check the picture below.