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chubhunter [2.5K]
3 years ago
10

Audra counted change collected for a class fundraiser. Audra wrote the equation to represent the situation. What did she define

as the variable x? value of a dime value of a quarter number of dimes collected number of quarters collected
Mathematics
2 answers:
dalvyx [7]3 years ago
8 0

Answer:

The X variable is defied as the number of dimes collected.

Step-by-step explanation:

The X is next to 10 cents so therefor i can instantly infer that it is talking about the dimes. The question is asking how many dimes were collected so then that means that x would have to multiply the dimes to count how much money they raised. So we can now fully infer that the X variable is defied as the number of dimes collected.

Nina [5.8K]3 years ago
6 0
If the equation has 0.1x, then it is number of dimes.
If the equation has 0.25x, then it is the number of quarters.
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Find the area of the polygon to the nearest square inch.
SVETLANKA909090 [29]

Answer:

137 in.^2

Step-by-step explanation:

A = nsa/2

where

n = number of sides = 9

s = length of side = 4.7 in.

a = length of apothem = 6.5 in.

A = (9)(4.7 in.)(6.5 in.)/2

A = 137.475 in.^2

Answer: 137 in.^2

5 0
3 years ago
Find the equation of the line passing through the points (-4,-5) and (4,1)
RoseWind [281]

Answer:

Y = 3/4x - 2

Step-by-step explanation:

Slope = (1 - - 5)/(4 - - 4 =6/8 = 3/4

b = -5 - (3/4)(-4)

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6 0
2 years ago
Melisa is throwing a birthday party for her son. She ordered 4 pizzas, she realizes that her son invited more people than she th
Liono4ka [1.6K]

Answer:

y = 3x + 4

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6 0
3 years ago
What would this be as a equation - 24 is the product of craigs savings and two
Kobotan [32]

Answer:

either -24=-12*2 or -12*2=-24

Step-by-step explanation:

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4 0
3 years ago
If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how
Goryan [66]

Rates are used to measure a quantity over another.

<em>The 1.8 million cars use </em>1.85 \times 10^{10}<em> liters each year</em>

Given

Cars = 1.8\ million

d = 17500km --- distance

r = 40miles/gallon

First, we calculate the number (n) of gallons used by each car

r = \frac{d}{n}

Solve for n

n = \frac{d}{r}

So, we have:

n = \frac{17500km}{40miles/gallon}

n = \frac{17500km}{40miles}gallon

Convert miles to kilometers

n = \frac{17500km}{40km \times 1.60934}gallon

n = \frac{17500km}{64.3738km}gallon

n = 271.85\ gallon

The number of gallons (N), used by all the cars is:

N = n \times cars

N = 271.85 \times 1.8\ million

N = 489330000

Convert to liters

N = 489330000 \times 3.78541L

N = 1852314675.3L

In scientific notation to 2 decimal places, we have:

N = 1.85 \times 10^{10}L

<em>Hence, the number of liters used is </em>1.85 \times 10^{10}<em />

Read more about distance and rates at:

brainly.com/question/24659604

4 0
3 years ago
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