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chubhunter [2.5K]
3 years ago
10

Audra counted change collected for a class fundraiser. Audra wrote the equation to represent the situation. What did she define

as the variable x? value of a dime value of a quarter number of dimes collected number of quarters collected
Mathematics
2 answers:
dalvyx [7]3 years ago
8 0

Answer:

The X variable is defied as the number of dimes collected.

Step-by-step explanation:

The X is next to 10 cents so therefor i can instantly infer that it is talking about the dimes. The question is asking how many dimes were collected so then that means that x would have to multiply the dimes to count how much money they raised. So we can now fully infer that the X variable is defied as the number of dimes collected.

Nina [5.8K]3 years ago
6 0
If the equation has 0.1x, then it is number of dimes.
If the equation has 0.25x, then it is the number of quarters.
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Arisa [49]

Answer:

sali's speed was 18.75 km/h

Step-by-step explanation:

Jane took 3.5 hours to cycle the 63 km.

As,   , so the speed of Jane will be:  

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Sali caught up with Jane when they had both cycled 30 km.

So, the time required for Jane to cycle 30 km  and the time required for Sali to cycle 30 km  

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5 0
3 years ago
PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (80pts)
Valentin [98]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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Rama09 [41]

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8 0
2 years ago
Consider the graph of the quadratic function y = 3x2 – 3x – 6. What are the solutions of the quadratic equation 0 = 3x2 − 3x − 6
son4ous [18]
Y = 3x^2 - 3x - 6 {the x^2 (x squared) makes it a quadratic formula, and I'm assuming this is what you meant...}

This is derived from:
y = ax^2 + bx + c

So, by using the 'sum and product' rule:

a × c = 3 × (-6) = -18

b = -3

Now, we find the 'sum' and the 'product' of these two numbers, where b is the 'sum' and a × c is the 'product':

The two numbers are: -6 and 3

Proof:

-6 × 3 = -18 {product}

-6 + 3 = -3 {sum}

Now, since a > 1, we divide a from the results

-6/a = -6/3 = -2

3/a = 3/3 = 1

We then implement these numbers into our equation:

(x - 2) × (x + 1) = 0 {derived from 3x^2 - 3x - 6 = 0}

To find x, we make x the subject of 0:

x - 2 = 0

OR

x + 1 = 0

Therefore:

x = 2

OR

x = -1

So the x-intercepts of the quadratic formula (or solutions to equation 3x^2 - 3x -6 = 0, to put it into your words) are 2 and -1.


We can check this by substituting the values for x:

Let's start with x = 2:

y = 3(2)^2 - 3(2) - 6
= 3(4) - 6 - 6
= 12 - 6 - 6
= 0 {so when x = 2, y = 0, which is correct}

For when x = -1:

y = 3(-1)^2 - 3(-1) - 6
= 3(1) + 3 - 6
= 3 + 3 - 6
= 0 {so when x = -1, y = 0, which is correct}
7 0
3 years ago
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poizon [28]

Answer:

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Then I added two line to find the center of the circle

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8 0
2 years ago
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