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2 years ago

What is the value of y when x=7?

Mathematics

2 answers:

Gwar [14]2 years ago

5 0

The value of y would be 60

The way you would solve this is by plugging in 7 for x.
After you plug in the 7 for x you would have to multiply 7 by 4 to get 28.
Next you would add 28 to 32 to get 60.
Your final answer should be y=60

Ksju [112]2 years ago

4 0

Y = 4x + 32 1. write the equation
y = 4(7) + 32 2. plug in missing numbers
y = 28 + 32 3. multiply 4 and 7
y = 60 4. add 28 and 32 to get final answer

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A bag of marbles contains 5 red, 3 blue, 2 green, and 2 yellow marbles. What is the probability that you choose a blue marble an

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PART ANSWER:

Hi. I don't know the entire answer but I do know the probability of chosing a blue marble once is 25%.

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Answer:

1377

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2 years ago

laiz [17]

Answer:

44x +56y = 95

Step-by-step explanation:

To write the equation of the perpendicular bisector, we need to know the midpoint and we need to know the differences of the coordinates.

The midpoint is the average of the coordinate values:

((-2.5, -2) +(3, 5))/2 = (0.5, 3)/2 = (0.25, 1.5) = (h, k)

The differences of the coordinates are ...

(3, 5) -(-2.5, -2) = (3 -(-2.5), 5 -(-2)) = (5.5, 7) = (Δx, Δy)

Then the perpendicular bisector equation can be written ...

Δx(x -h) +Δy(y -k) = 0

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5.5x -1.375 +7y -10.5 = 0

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3 years ago

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natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$ </em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

<u>Formula for the coordinate of mid-point</u> : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be: $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be: $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

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