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masya89 [10]
3 years ago
8

PLEASE help — I’m failing!

Chemistry
1 answer:
ANEK [815]3 years ago
4 0

Answer:

a.

[H _{3}O {}^{ + }   ] = 4.23 \times  {10}^{ - 3} M

b.

[OH {}^{ - } ] =  \frac{kw}{[H {}^{ + } ]}  \\ [OH {}^{ - } ] =  \frac{1 \times  {10}^{ - 14} }{4.23 \times  {10}^{ - 3} }  \\ [OH {}^{ - } ] = 2.36 \times  {10}^{ - 12} M

c.

pH =  -  log[H {}^{ + } ] \\ pH =  -  log(4.23 \times  {10}^{ - 3} )  \\ pH = 2.37

d.

pOH =  -  log[OH {}^{ - } ] \\  =  -  log(2.36 \times  {10}^{ - 12} )  \\  = 11.63

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Answer:

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Explanation:

Given data:

Mass of Ca(OH)₂ = ?

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