(Not guaranteed correct answer)
Balanced equation for complete combustion of methane would be:
CH4 + 2O2 --> CO2 + 2H20
Amount of CO2:
22g / [12.0+2(16.0)]
= 0.5mol
Mole ratio can be represented as
CH4 = CO2
So 0.5 mol of CO2 = 0.5 mol of CH4 ??
To calculate<span> the average </span>atomic mass<span>, multiply the fraction by the </span>mass<span> number for each isotope, then add them together.</span>
3x10^8 / (670.8 * 10^-9) =4.47x10^14 Hz 4.47x10^14 Hz multiplied by plank's constant = 2.9634x10^-19
2.96 x10-19 J
Answer:
1.67 M
Explanation:
75.0 g *1 mol/180 g = (75/180) mol of glucose
250 mL = 0.250 L
(75/180)/0.250 = 1.67 mol/L =1.67 M
Answer:
Explanation:
I am assuming you are saying what is the final volume of the gas
Known :
Initial volume (V1) = V
Initial temperature (T1) = T
Final temperature (T2) = 5/4 T
Initial pressure (P1) = P
Final pressure (P2) = 2P
<u>Wanted: Final volume (V2)</u>
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