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dedylja [7]
3 years ago
8

How many grams of Ca(OH)2are required to make 1.5 L of a 0.81 M solution?

Chemistry
1 answer:
FrozenT [24]3 years ago
5 0

Answer:

Mass = 90.28 g

Explanation:

Given data:

Mass of Ca(OH)₂ = ?

Volume of solution= 1.5 L

Molarity of solution = 0.81 M

Solution:

First of all we will calculate number of moles.

Molarity = number of moles / volume in L

by putting values,

0.81 M = Number of moles / 1.5 L

Number of moles = 0.81 M × 1.5 L

Number of moles = 1.22 mol

Mass of Ca(OH)₂ in gram:

Mass = number of moles × molar mass

Mass = 1.22 mol × 74.09 g/mol

Mass = 90.28 g

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<h3>What is the formula for exponential decay?</h3>
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Here,

a = the initial amount of substance

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The equation is given in its correct form as follows:

a = a_{0}×(0.8)^{t}

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<h3>Substituting this into the equation:</h3>

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0.5 = (0.8)^{t}

taking log on both sides

t log 0.8 = log 0.5

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t = 3.106 years

The half-life of the substance is 3.106 years.

To learn more about exponential decay formula visit:

brainly.com/question/28172854

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