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Alenkinab [10]
3 years ago
7

What is the value of y in the following system? y=3x-5 6x+3y=15

Mathematics
2 answers:
charle [14.2K]3 years ago
8 0

Step-by-step explanation:

y=3x-5

6x+3y=15

6x+3(3x-5)=15

6x+9x-15=15

15x-15=15

+15 +15

15x=30

/15. /15

x=2

6(2)+3y=15

12+3y=15

-12. -12

3y=3

/3 /3

y=1

(2,1)

The answer is (2,1)

8090 [49]3 years ago
6 0

Step-by-step explanation:

6x + 3(3x - 5) = 15

6x + 9x - 15 = 15

15x - 15 = 15

+15 +15

15x = 30

/15 /15

x = 2

6(2) + 3y = 15

12 + 3y = 15

-12 -12

3y = 3

/3 /3

y = 1

(2, 1)

This should be right if it is please make me brainliest.

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May I please get the answers to the first 4 of these problems?
Ugo [173]
Given:
A(3,0)
B(1,-2)
C(3,-5)
D(7,-1)

1) reflect across x=-4
essentially calculate the difference between the x=-4 line and Px and "add" it in the other direction to x=-4
A(-4-(3-(-4)),0)=A(-11,0)
B(-4-(1-(-4)),-2)=B(-9,-2)
C(-4-(3-(-4),-5))=C(11,-5)
D(-4-(7-(-4)),-1)=D(-15,-1)

2) translate (x,y)->(x-6,y+8)
A(-3,8)
B(-5,6)
C(-3,3)
D(1,7)

3) clockwise 90° rotation around (0,0), flip the x&y coordinates and then decide the signs they should have based on the quadrant they should be in
A(0,-3)
B(-2,-1)
C(-5,-3)
D(-1,-7)

D) Dilation at (0,0) with scale 2/3, essentially multiply all coordinates with the scale, the simple case of dilation, because the center point is at the origin (0,0)
A((2/3)*3,(2/3)*0)=A(2,0)
B((2/3)*1,(2/3)*-2)=B(2/3,-4/3)
C((2/3)*3,(2/3)*-5)=C(2,-10/3)
D((2/3)*7,(2/3)*-1)=D(14/3,-2/3)
7 0
3 years ago
Use the quadratic formula to solve the equation <br> 25x^2-30x+25=0
Reika [66]

Answer: x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}

Step-by-step explanation:

25x^2-30x+25=0

x_{1,\:2}=\frac{-\left(-30\right)\pm \sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}}{2\cdot \:25}

\sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}

=\sqrt{30^2-4\cdot \:25\cdot \:25}

=\sqrt{30^2-2500}

=i\sqrt{2500-30^2}

=40i

x_{1,\:2}=\frac{-\left(-30\right)\pm \:40i}{2\cdot \:25}

x_1=\frac{-\left(-30\right)+40i}{2\cdot \:25},\:x_2=\frac{-\left(-30\right)-40i}{2\cdot \:25}

x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}

8 0
3 years ago
Plz, Help me with this!!!!
yanalaym [24]
It’s 152y+125, basically by simplifying
6 0
3 years ago
Read 2 more answers
Pls hurry
AlladinOne [14]

Step-by-step explanation:

To evaluate, substitute 29 for the variable in the expression.

To evaluate, substitute 31 for the variable in the equation.

To evaluate the expression, add 31 to 29.

The correct expression is n-31.

To evaluate the expression, subtract 31 from 29Pls hurry

Rafael writes an expression to represent "a number, n, decreased by thirty-one." Then he evaluates that expression if

n-29. Which statements are true about the expression and its evaluation? Check all that apply.

The correct expression is 31-n.

This is a subtraction expression.

This is an addition expression.

To evaluate, substitute 29 for the variable in the expression.

To evaluate, substitute 31 for the variable in the equation.

To evaluate the expression, add 31 to 29.

The correct expression is n-31.

To evaluate the expression, subtract 31 from 29..

4 0
3 years ago
Read 2 more answers
What is the quotient (x3 – 3x2 + 5x – 3) ÷ (x – 1)?
11111nata11111 [884]

Answer:

  1. x^2 -2x +3
  2. x^2 +2x +3

Step-by-step explanation:

The quotient in each case can be found by any of several means, including synthetic division (possibly the easiest), polynomial long division, or graphing.

1. The graph shows you the quotient is (x-1)^2 +2 = x^2 -2x +3.

2. The graph shows you the quotient is (x+1)^2 +2 = x^2 +2x +3.

3 0
3 years ago
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