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3 years ago

What is the value of y in the following system? y=3x-5 6x+3y=15

Mathematics

2 answers:

charle [14.2K]3 years ago

8 0

Step-by-step explanation:

y=3x-5

6x+3y=15

6x+3(3x-5)=15

6x+9x-15=15

15x-15=15

+15 +15

15x=30

/15. /15

x=2

6(2)+3y=15

12+3y=15

-12. -12

3y=3

/3 /3

y=1

(2,1)

The answer is (2,1)

8090 [49]3 years ago

6 0

Step-by-step explanation:

6x + 3(3x - 5) = 15

6x + 9x - 15 = 15

15x - 15 = 15

+15 +15

15x = 30

/15 /15

x = 2

6(2) + 3y = 15

12 + 3y = 15

-12 -12

3y = 3

/3 /3

y = 1

(2, 1)

This should be right if it is please make me brainliest.

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Two angles are supplementary the measure of one angle is 4 times the measure of the other angle what is the measure of the small

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3 years ago

Please help me! Find the number x such that f(x) =1

STatiana [176]

Answer:

Step-by-step explanation:

We have the piecewise function:

$f(x) = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

$1 = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

This has two equations. So, we can separate them into two separate cases. Namely:

$1=-\frac{1}{2}x-1\text{ or } 1=x$

Let's solve for x in each case.

Case I:

We have:

$1=-\frac{1}{2}x-1$

Add 1 to both sides:

$2=-\frac{1}{2}x$

Let's cancel out the fraction by multiplying both sides by -2. So:

$2(-2)=(-2)\frac{-1}{2}x$

The right side cancels:

$-4=x\\$

Flip:

$x=-4$

So, x is -4.

Case II:

We have:

$1=x$

Flip:

$x=1$

This is the solution for our second case.

So, we have:

$x_1=-4\text{ or } x_2=1$

Now, can check to see if we have to to remove solution(s) that don't work.

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The first equation is defined only if x is less than -2.

-4 is less than -2. So, x=-4 is indeed a solution.

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1 is greater than or equal to -2. So, x=1 is also a solution.

Therefore, our two solutions are:

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Out of our answer choices, we can pick D.

And we're done!

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