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slava [35]
3 years ago
15

A bridge has a single lane and is 122 feet long. The weight limit for the bridge is 20 tons. Each car that might be on the bridg

e is 7.4 feet long and weighs 1.2 tons. Each truck is 16 feet long and weighs 2.8 tons. Write an inequality you could use to find the number of trucks t that can fit on the bridge when there are 10 cars in the bridge.
Mathematics
1 answer:
gulaghasi [49]3 years ago
6 0

Answer:

2.8 t ≤  12 tons  ,  16 t  ≤   48 feet are the required inequalities to find the number of trucks t on a bridge.

Step-by-step explanation:

The number of trucks on the bridge = t

Number of cars = 10

Total length of Bridge = 122 ft, and weight = 20 tons

Total length of Car = 7.4 ft, and weight = 1.2 tons

Total length of truck = 16 ft, and weight = 2.8 tons

Now, there are 10 cars on the bridge.

So, total length of bridge covered = 7.4 x 10 = 74 feet

Hence, the available length of bridge for trucks = 122 - 74 = 48 ft

Also, total weight of bridge covered = 1.2 x 10 = 12 tons

Hence, the available weight  of bridge for trucks = 20 - 12 = 8 tons

Hence, according to the question:

2.8 t ≤  12 tons    and

16 t  ≤   48 feet are the required inequalities to find the number of trucks t on a bridge.

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Darya [45]
The second one is correct
7 0
3 years ago
A random sample of 25 ACME employees showed the average number of vacation days taken during the year is 18.3 days with a standa
Norma-Jean [14]

Answer:

a) Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

b) df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

c) Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

Step-by-step explanation:

Data given and notation  

\bar X=18.3 represent the sample mean

s=3.72 represent the sample standard deviation

n=25 sample size  

\mu_o =15 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean for vacation days is higher than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: P-value  and conclusion

The first step is calculate the degrees of freedom, on this case:  

df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

Part c

Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

3 0
3 years ago
What factors of 20 are also factors of 50
spayn [35]
The easiest way to find the factors of a pair of numbers, is simply to write out the factors until you find the ones that they have in common. So in this case, these factors would be listed as follows:
20: 1,2,4,5,10,20
50: 1,2,5,10,25,50.
From looking at these numbers, we can therefore see that the common factors are: 1,2,5,10
7 0
3 years ago
Read 2 more answers
What is 3+2-8+9+8+0-6-9+8
monitta

Answer:

7

Step-by-step explanation:

First,

3+2=5

5-8=-3

-3+9=6

6+8=14

14+0=14

14-6=8

8-9=-1

-1+8=7

8 0
3 years ago
Since it's Wednesday, Buy for Less gives a 5% discount for purchases. The items in Rhonda's cart total $53.75. She needs to know
Aleksandr-060686 [28]

First we need to know how much the discount was so 5% is actually 0.05 then we need to multiply it by 53.75 which would equal 2.6875 then subtract it by 53.75 which would equal -51.0625.

B) .95(53.75)

This is a trick question because D) could also be correct if they said you could subtract it but it's not saying use the distributive property.

5 0
3 years ago
Read 2 more answers
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